(5.736) 10^23 atoms
There are 5 atoms in the molecule HNO3. 1 hydrogen, 1 nitrogen and 3 oxygen atoms. Hope this helps!!:)I loveSelenaGomez.:)
Elements which have two or more different types of atoms are known as multi-atomic elements. eg; HClO4, HNO3 etc.
The chemical formula for Hydrogen Nitrate is: HNO3
alcl3+hno3
Hydrogen and nitrogen are both elements. That means that neither of them are made up of other elements. A hydrogen molecule is just two atoms of hydrogen. Nitrogen is just atoms of nitrogen.
HNO3 is consist of 1 hydrogen atom, 1 nitrogen ato and 3 oxygen atoms. That means there are 5 atoms in 1 HNO3. So there are 20 atoms in 4 HNO3.
There are 5 atoms in the molecule HNO3. 1 hydrogen, 1 nitrogen and 3 oxygen atoms. Hope this helps!!:)I loveSelenaGomez.:)
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4HNO3 means HNO3 + HNO3 + HNO3 + HNO3 Taking any one HNO3 it has 1 x H (Hydrogen) 1 x N (Nitrogen) 3 x O (Oxygen) 1 + 1 + 3 = 5 So any one HNO3 has five atoms. So four lots of HNO3 has 4 X 5 =20 atoms. So no. of each type is 4 x hydrogen 4 x Nitrogen 12 x Oxygen 4 + 4 +12 = 20 as above. 4HNO3 would be said as 'Four molar ratios of nitric acid'.
In HNO3 or nitric acid, there are three elements - hydrogen, nitrogen and oxygen. The atoms are present in the ratio 1:1:3. All three atoms are of non-metals.HNO3 is an acid. It has 5 atoms. They are, Hydrogen, Nitrogen, Oxygen.
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It is a neutralization.KNO3 formed with water. KOH+HNO3 -->KNO3+H2O
Two ions make up HNO3. Anion is NO3- and cation is H+.
Concentration of NaOH = 0.025 M = 0.025 Moles per Litre of SolutionVolume of Solution required = 5.00LWe can say therefore that:Number of Moles of NaOH needed to prepare the solution= Concentration of NaOH * Volume of Solution requiredTherefore:Number of Moles of NaOH needed to prepare the solution= 0.025M * 5.00L= 0.125molesFrom this we can say that 0.125 moles of NaOH are needed to prepare a 5.00 L solution with a concentration of 0.025M of NaOH.
For this you need the atomic (molecular) mass of HNO3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. HNO3= 63.0 grams2.00 moles HNO3 × (63.0 grams) = 126 grams HNO3
Each mol (of any substance) is 6.022*10+23 molecules, and each molecule HNO3 has 4 atoms, so you'll find the answer by multiplying these figures.The outcome will be (as correctly rounded estimate) 2.2*10+23 atoms in 0.093 mol HNO3