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sulphur has 6 v.e

f has 7 each

so total 34 v.e

sf4 has a trigonbal bipyramidal structure.

it has 1 lone pair of electrons too. "which do not enter into bonding

sf6 is possible too.

actually...

a trgonal byprimidal is a structure with 5 electron groups (Bonding electrons + lone pair electrons). SF4 only has 4 electron groups around it,(all valnce electrons bonded with fluorine and no lone pairs) so it is actually has a tetrahedral geometry. sp^3.

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12y ago
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10y ago

It has 33 valence elctrons

N has 5 because 2 in the s orbital and 3 in the p

F has 7 because 2 are in the s orbital and 5 in the p and there are 4 Fluorine atoms

so 5+7(4) = 33

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10y ago

I think the question needs to be revised. You consider atoms to have valance electrons, i.e. how many electrons in its outermost energy level. Carbon has 4 valence electrons and fluorine has 7 each. However, if you are talking about the molecule C2F4, you have 3x SP2 hybridisation of each carbon, 1 each the carbon carbon bonds (along with the spare P orbital) to create a double bond between carbons, and the remaining 2 sp2s of each bond the fluorines. I.e. in that conformation, there are no more electrons available for bonding

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11y ago

16. 4 pairs are used in bonding, there are 3 lone pairs on each F.

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14y ago

32

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Q: How many valence electrons are in NF4?
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