sulphur has 6 v.e
f has 7 each
so total 34 v.e
sf4 has a trigonbal bipyramidal structure.
it has 1 lone pair of electrons too. "which do not enter into bonding
sf6 is possible too.
actually...
a trgonal byprimidal is a structure with 5 electron groups (Bonding electrons + lone pair electrons). SF4 only has 4 electron groups around it,(all valnce electrons bonded with fluorine and no lone pairs) so it is actually has a tetrahedral geometry. sp^3.
It has 33 valence elctrons
N has 5 because 2 in the s orbital and 3 in the p
F has 7 because 2 are in the s orbital and 5 in the p and there are 4 Fluorine atoms
so 5+7(4) = 33
I think the question needs to be revised. You consider atoms to have valance electrons, i.e. how many electrons in its outermost energy level. Carbon has 4 valence electrons and fluorine has 7 each. However, if you are talking about the molecule C2F4, you have 3x SP2 hybridisation of each carbon, 1 each the carbon carbon bonds (along with the spare P orbital) to create a double bond between carbons, and the remaining 2 sp2s of each bond the fluorines. I.e. in that conformation, there are no more electrons available for bonding
16. 4 pairs are used in bonding, there are 3 lone pairs on each F.
32
5 valence electrons.
6 Valence Electrons
There are 8 valence electrons for neon.
4V V-Valence Electrons Valence Electrons-Last electron (which is on the outer shell)
5 valence electrons exist in bromine period, at ground state bromine has 3 valence electrons
6 valence electrons
how many valence electrons does family 1 have
3 valence electrons.
10 valence electrons
8 valence electrons
8 valence electrons
3 valence electrons
5 valence electrons.
3 valence electrons
Beryllium has two valence electrons.
Cl has 7 valence electrons.
Valence electrons are placed in the outermost shell of electrons.