Your question answers itself... 1000 watts, when operated on a 480-volt source..
No, they do not draw the same current. The current drawn by an electrical device is determined by the power (Watts) and voltage (Volts) using the formula: Current (amps) = Power (Watts) / Voltage (Volts). So, the 12 volt 50 watt bulb will draw higher current compared to the 230 volt 50 watt bulb.
In a parallel circuit, each load added subtracts from total resistance. When one or more loads is removed from a parallel circuit, the total resistance is increased, reducing the total amperage draw. The less resistance a load has, the more current can pass through. This is part of Ohm's law. The mathematical equation that describes Ohm's law is: I=V/R , where I is the current in amperes, V is the potential difference in volts,and R is a circuit parameter called the resistance For example : The humble light-bulb is rated by the watts it uses. The amount of watts used by a light-bulb is calculated using Ohm's law. With the resistance of the bulb's filament and the voltage the bulb is designed to operate with, one can derive the amperage the bulb will draw. The amperage is then multiplied by the voltage to show wattage. Using Ohm's law : With the resistance of a 40watt 120volt light-bulb, only 0.33amps is able to pass through the bulb's 363ohm filament at 120volts. A lamp that has two 40watt bulbs inplace, and the two bulbs are in parallel, the circuit will have a resistance of 179ohms and draw 0.67amps which is 80watts at 120volts.
I'm unable to draw images. Would you like a description of the rock cycle instead?
A kVA is 1000 watts. Where k stands for kilo or 1000. V for volts A for amperes. A watt is a volt X a ampere. Mega means 1 000 000 so a megawatt= 1000 kVA. Note: This is only true for resistive loads like heaters and lightbulbs.AnswerYou cannot really ask 'How many watts equal how many volt amperes?', because you are describing two different quantities, as explained below:Alternating-current loads are often combinations of resistance and reactance (reactance is the opposition to current due to either inductance, or capacitance, or a combination of both).Loads having both resistance and reactance exhibit true power and reactive power.True power describes the rate at which energy is permanently lost due to the resulting temperature difference between the conductor(s) and the surroundings. True power is associated with purely resistive loads, and is expressed in watts.Reactive power describes the rate at which energy is alternately stored in a magnetic or electric field then returned to the supply. Reactive power is associated with purely reactive loads, and is expressed in reactive volt amperes.Apparent power is the vector sum of true power and reactive power, and is expressed in volt amperes.The relationship between true power and apparent power is:true power = apparent power x power factorPower factor varies from zero (purely reactive circuit) to unity (purely resistive circuit). So, true power (in watts) will only equal apparent power (in volt amperes) when the power factor is unity -i.e. in a purely resistive circuit. For all other types of circuit, the true power will always be less than the apparent power.
To draw the water cycle, start by drawing bodies of water (ocean, lake, river) with arrows moving up to represent evaporation. Label this process as "Evaporation." Next, draw clouds in the sky with arrows moving down to represent condensation. Label this process as "Condensation." Lastly, draw arrows moving from the clouds down to the ground to represent precipitation, and label this as "Precipitation." Connect all three processes in a circle to show the continuous cycle of water.
There is a small current draw taking place to keep the dusk to dawn circuit activated.
It will draw 150 watts. The capacitor is there only to increase the voltage enough to "excite" the free electrons in the gas to ignite.
Depends on the size of the LED light and the voltage applied. An example is an LED 24 volt globe light that pulls 8 watts which draw 0.333333 amps. Take an LED 120 volt light bulb draws 12 watts and will pull 0.1 amps. The same bulb at 240 volts wil draw 0.05 amps. it really depends on the watts and voltage applied. An average would be about 0.1 amps.
Ask not what you can draw for Sports Illustrated, but what Sports Illustrated can draw for you.
The kilowatt power draw of the electric furnace can be calculated using the formula: Power (kW) = Current (A) x Voltage (V) / 1000. Plugging in the values (20 A and 240 V) into the formula, we get: Power = 20 A x 240 V / 1000 = 4.8 kW. Therefore, the electric furnace has a power draw of 4.8 kilowatts.
1100 watts or about ten amps then another 3 to 4 amps for turn table light and fan
A 1000 watt ballast operating at 120V would draw approximately 8.33 amps of current. This can be calculated by dividing the power (in watts) by the voltage (in volts).
the older furnaces would draw 700 watts plus depending on the size of the blower. the newer furnaces with variable speed blowers can draw as little as 100 watts
To calculate the amperage draw, you need to know the voltage of the circuit where the 2500 watts appliance will be used. You can use the formula: Amps = Watts / Volts. For example, if it is a 120V circuit, the amperage draw would be 2500 watts / 120 volts = 20.83 amps.
There are zero amps in 1000 watts. Watts are the product of amps x volts or I = W/E, watts divided by voltage. As you can see, that if no voltage is stated no amperage can be given. Once you find the voltage of the heater then use the following equation, Amps = Watts/Volts to find the current draw of the 1000 watt heater.
Watts = Amps x volts. What is the current draw and voltage of the calculator.
the older furnaces would draw 700 watts plus depending on the size of the blower. the newer furnaces with variable speed blowers can draw as little as 100 watts