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How do you find the number of atoms in 6.21 mol of Mg?
To find the number of atoms in 6.21 mol of Mg, you would use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, for 6.21 mol of Mg, you would multiply the number of moles by Avogadro's number to get the number of atoms.
How many atoms are in 12g of magnesium?
Amount of Mg = 12/24.3 = 0.494mol 1 mol of Mg contains 6.02 x 1023 Mg atoms (avogadro constant). Number of atoms in 12g of Mg = 0.494 x 6.02 x 1023 = 2.97 x 1023
Mass of 3.65 mol Mg?
To solve this first the molar mass of Mg is needed (look at a periodic table). (Mg=23.0g/mol) Then convert the mols to grams as follows: (3.65 mol Mg) x (23.0 g/mol Mg) = 84.0 g Mg The mol units cancel in the conversion leaving only the gram units and the ammount in grams.
What is the mass in mg of thanol of 5.1 1020 molecules of ethanol?
To calculate the mass of 5.1 x 10^20 molecules of ethanol, first determine the molar mass of ethanol (46.07 g/mol). Then convert this to mg/mol (46,070 mg/mol). Finally, multiply the molar mass by the number of molecules to find the total mass in mg (approximately 2.35 x 10^25 mg).
What is the molecular weight of magnesium acetate?
Lets start off by stating the chemical formula so we can figure out the molecular mass easier. The formula for magnesium acetate is Mg(CH3COO)2 but can also be written as (CH3COO)2Mg (this helps when we are creating a VSEPR diagram). So now that we know the formula we can figure out what the mass is. We take the atomic mass of each atom in the molecule and add them together like so: 24.31g/mol+ 2(12.01 g/mol+ (3 x 1.01g/mol)+ 12.01g/mol + 16.00g/mol+ 16.00g/mol) = 142.41 g/mol
How do you find the number of atoms in 6.21 mol of Mg?
To find the number of atoms in 6.21 mol of Mg, you would use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, for 6.21 mol of Mg, you would multiply the number of moles by Avogadro's number to get the number of atoms.
How many moles of atoms are there in 7.25 x 10 23 atoms mg answer in units of mol?
1.203mol
How many atoms are in 12g of magnesium?
Amount of Mg = 12/24.3 = 0.494mol 1 mol of Mg contains 6.02 x 1023 Mg atoms (avogadro constant). Number of atoms in 12g of Mg = 0.494 x 6.02 x 1023 = 2.97 x 1023
Explain why there are 1.2 x 1024 atoms in 1 mol of H2 and yet there are only 6.02 x 1023 atoms in 1 mol of Mg?
1+1=2 therefore apple = apple and then you take grams per mol. end
How many moles of magnesium are 12.04 x 10 23 atoms?
1 mole Mg = 6.022 x 1023 atoms Mg 12.04 x 1023 atoms Mg x 1mol Mg/6.022 x 1023 atoms Mg = 1.999 moles Mg
One 55-gram serving of a particular cereal supplies 270 mg of sodium 11 of the recommended daily allowance. How many moles and atoms of sodium are in the recommended daily allowance?
The recommended daily allowance of sodium is approximately 2,300 mg. To find the number of moles, divide this amount by the molar mass of sodium (approximately 23 g/mol): ( \frac{2300 , \text{mg}}{23,000 , \text{mg/mol}} \approx 0.1 , \text{mol} ). Since one mole of sodium contains Avogadro's number (approximately ( 6.022 \times 10^{23} )) of atoms, the total number of sodium atoms in the recommended daily allowance is about ( 0.1 , \text{mol} \times 6.022 \times 10^{23} , \text{atoms/mol} \approx 6.022 \times 10^{22} ) atoms.
What is the formula mass of Mg(NO3)2?
The formula mass of Mg(NO3)2, also known as magnesium nitrate, is 148.32 g/mol. This is calculated by adding the atomic masses of magnesium (24.31 g/mol), nitrogen (14.01 g/mol), and three oxygen atoms (16.00 g/mol each) together.
Mass of 3.65 mol Mg?
To solve this first the molar mass of Mg is needed (look at a periodic table). (Mg=23.0g/mol) Then convert the mols to grams as follows: (3.65 mol Mg) x (23.0 g/mol Mg) = 84.0 g Mg The mol units cancel in the conversion leaving only the gram units and the ammount in grams.
3 atoms of magnesium combine with 2 atoms of nitrogen.What will be the weight of magnesium which combines with 1.86g of nitrogen?
Equation: 3Mg + N2 → Mg3N2 3mol Mg combines with 1mol N2. Molar mass N2 = 28.014g/mol 1.86g N2 = 1.86/28.014 = 0.0664mol N2 This will require 0.0664*3 = 0.1992mol Mg Molar mass Mg = 24.305g/mol 0.1992mol Mg = 24.305*0.1992 = 4.84g Mg required.
How many atoms of calcium are in 80.0 grams of calcium?
You need to know the molar mass for Ca which is: 40.078 g/mol and avrogadros # or whatever which is: 6.022 x 10^23So:80.0g Ca x (1 mol Ca / 40.078 g Ca) = 1.996 mol Ca (this eliminated grams)1.996 mol Ca x (6.022 x 10^23 atoms / 1 mol Ca) = 1.202 x 10^24 atoms of calciumJust remember the fraction 6.022 x 10^23 atoms / 1 mol ! It's the same thing so you can flip it!
How many atoms in one gram of magnesium?
1 mole Mg = 6.022 x 1023 atoms 1 mole Mg = 24.3050g (atomic weight in grams) 1g Mg x (1mol/24.3050g) x (6.022 x 1023atoms/mol) = 2 x 1023 atoms (rounded to 1 significant figure)
What is the formula mass of magnesium chlorate Mg ClO3 2 to 2 decimal places?
The formula mass of magnesium chlorate (Mg(ClO3)2) is calculated by adding the atomic masses of one magnesium atom, two chlorine atoms, and six oxygen atoms. The atomic mass of magnesium is 24.31 g/mol, chlorine is 35.45 g/mol, and oxygen is 16.00 g/mol. Therefore, the formula mass of Mg(ClO3)2 is (124.31) + (235.45) + (6*16.00) = 148.72 g/mol.
