How much does 1 gallon of ferric sulfate weigh?

Answer 1

Density = Mass/Volume

Density of sulfur = 2.07 g.cm-3.

1 cubic yard ≈ 0.764544858 m3

(1 g)(1 kg)(1 000 000 cm3)

____________________________ = 1 000 000 kg/1000 m = 1000 kg/m3

(1 cm3)(1000 g)(1 m3)

SO:

D=M/V

D=2.07g/cm3 = 2070 kg/m³

M=x

V=0.764544858 m³

2070 kg/ 1 m3 = x/0.764544858 m³

x 0.764544858 m³ = x 0.764544858 m³

________________________________

Or about:

3 489.1 Pounds

1.7445 Tons

1.583 Tonnes

Answer 2

a gallon of water weighs 8.34 lbs. If the specific gravity of ferric sulfate is known you can calculate from that. It depends on how heavyor concentrated your liquid sample is