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The weight of 1 liter of air depends on the composition of the air, the temperature, the pressure, and the gravitational field it is subject to.

As an example, let us assume air of composition:

79 mole% N2 (nitrogen)

20 mole% O2 (oxygen)

1 mole % Ar (argon)

This would give an average molecular weight of

0.79x28.01335 + 0.20x31.9988 + 0.01x39.948 = 28.930 or 28.930 g/mole

At 0 °C and 1 bar pressure 1 mole of gas occupies 22.4 liters, i.e. 22.4 liters/mole

hence we have 28.930/22.4 = 1.29 g/liter

At normal earth gravity this would weigh 0.0127 N (Newtons) or 0.00285 lbf or 0.0456 ounces.

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13y ago

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