58 g NaCl = 58 (g) / 58.44 (g/mol NaCl) = 0.9925 (mol NaCl) = 0.9925 (mol Cl-) = 0.9925 * 35.45 (g/mol Cl-) = 35.2 g Cl-
By adding calcium chloride to sodium chloride, the melting point of the mixture is reduced because calcium chloride is a salt that disrupts the sodium chloride lattice structure. This disruption makes it easier for the sodium chloride to transition from a solid to a liquid state, lowering its melting point.
The molar mass of NaCl is 58.44 g/mol. To calculate the molarity, first convert grams to moles (58 g / 58.44 g/mol = 0.993 mol). Then divide moles by liters of solution (0.993 mol / 1.0 L = 0.993 M). Therefore, the molarity of the solution is 0.993 M.
The percent composition of NaOH can be calculated by dividing the mass of each element by the molar mass of NaOH and then multiplying by 100. For NaOH, the percent composition is approximately 39% Na (sodium) and 61% O (oxygen), as there is only one atom of each in the compound.
Normal saline (0.9% NaCl) has a concentration of 154 milliequivalents per liter of sodium. This means that a 1L bag of normal saline would contain 154 milliequivalents of sodium.
80-32/1.8 58/1.8 58/2=29 ~30
To make a 100ml 1M solution of Sodium Chloride, you would dissolve 5.85 grams of NaCl in enough water to make 100ml of solution. This molarity calculation is based on the molar mass of NaCl (58.44 g/mol).
For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58 grams 25.0 grams NaCl / (58 grams) = .431* moles NaCl *approximation
Answer: The mass of NaCl is, 219.15 grams Explanation: Given, Moles of NaCl = 3.75 mole Molar mass of NaCl = 22.99 + 35.45 = 58.44 g/mole Formula used : Now put all the given values in this formula, we get the mass of NaCl. Therefore, the mass of NaCl is, 219.15 grams
The molecular weight of sodium (Na) is 22.99 grams. The molecular weight of chlorine (Cl) is 35.45 grams. Therefore, there are 58.44 grams in 1 mole of NaCl. So, in 3.25 moles of NaCl, there are 58.44 gr x 3.25 = 189.93 grams.
2 * [(Na=23) + (Cl=35.5)] = 117 grams NaCl
We just use stoichiometry. The molecular formula for sodium chloride is NaCl. First we must find the molar mass of NaCl, using the molar masses of each element in the compound. So, 23 g/mol of Na + 36 g/mol of Cl = 58 g/mol of NaCl. Next, we take the amount of grams you have (26 grams) and divide it by the molar mass of NaCl to find the number of moles in your sample. 26 g NaCl / 58 g/mol of NaCl = .45 mol NaCl. Finally, we convert that to the number of NaCl molecules in a mole by multiplying .45 moles by 6.02x1023. This equals 2.7x1023 molecules. Because, technically, NaCl is made up of 2 atoms per molecule, you can multiply that by 2, giving 5.7x1023 atoms.
To calculate the molarity, you first need to convert the mass of NaCl to moles using its molar mass. The molar mass of NaCl is approximately 58.5 g/mol. Then, divide the moles of NaCl by the volume of the solution in liters to get the molarity. In this case, molarity = (58 grams / 58.5 g/mol) / 2.0 L.
When a mixture of 42% NaCl and 58% CaCl2 is electrolysed in Down'cell pure molten sodium metal is obtained.
A mole weighs 58 grams
The molecular weight of NaCl is 58.44. So you would need to add 116.88 g of NaCl into 1 L of water. Molarity X Required volume X Molecular weight 2 M/L X 1 L X 58.44 =116.88 g/L
58 grams = 2.045889794 ounces
By adding calcium chloride to sodium chloride, the melting point of the mixture is reduced because calcium chloride is a salt that disrupts the sodium chloride lattice structure. This disruption makes it easier for the sodium chloride to transition from a solid to a liquid state, lowering its melting point.