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q=mc(Tf-Ti)

assume 100 ml = 100 g

c=4.184 J/Kg

q=(100g)(4.184J/Kg)(22.4-25.3)

q=-1213.36J

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Q: How much heat is absorbed by 100 mL of a dilute solution of NH4NO3 as it changes its temp from 25.3 Celsius to 22.4 Celsius?
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