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99 Liters of water. If there are 20,000 ppm of iron nitrate in 1 liter of water then you would need to reduce the iron nitrate concnetration by a factor of 100. So since you are only adding water you need to have 100 times as much water than you had originally in order to dilute the concentration to 200 ppm. Since you have 1 liter already you need to add 99 more to get 100 times more water than you originally started with. You can also solve it using the following equation:

(Original Concnetration)*(Vol. original concentration) = (New concnetration)*(Original volume + amt of water to add)

20,000*1L = 200*(1L + X)20,000=200 + 200XSolving for X, X=99

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