Bromine becomes basic.
Potassium (K) has 1 valence electron which is loses to become K^+. Fluorine has 7 valence electrons and picks up the 1 electron lost by K, and it becomes F^-. They attract each other to become KF.
i was hoping somebody else would noo arg!! my science teacher mss Edwards is asking me al these questions and i cant figure them out at all .. of well let me no guyz love hollie x Potassium bromide (KBr) is water soluble, when met with water it will dissolve. The dissolution of KBr in water is an endothermic reaction, the enthalpy change is about +19.8 Kj/mol. Does anyone know why the solution process occurs even though the enthalpy is a relatively high positive number which should mean weaker bonds?
no colour change
nothing happens but you can add iodine then it will change coulur
you will get potassium bromide
holaaa lala
Bromine becomes basic.
It is left as a low hazard
a dipole in induced.
bromine is reduced
bromine is reduced
Potassium loses one electron to form K+ ion that has the noble gas configuration of the element neon.
The potassium atom gives up one electron, and the sulfur atom acquires two electrons (hence, it takes two potassium and one sulfur to form potassium sulfide, K2S).
Potassium (K) has 1 valence electron which is loses to become K^+. Fluorine has 7 valence electrons and picks up the 1 electron lost by K, and it becomes F^-. They attract each other to become KF.
i was hoping somebody else would noo arg!! my science teacher mss Edwards is asking me al these questions and i cant figure them out at all .. of well let me no guyz love hollie x Potassium bromide (KBr) is water soluble, when met with water it will dissolve. The dissolution of KBr in water is an endothermic reaction, the enthalpy change is about +19.8 Kj/mol. Does anyone know why the solution process occurs even though the enthalpy is a relatively high positive number which should mean weaker bonds?
When Bromine is mixed with Benzene it becomes bromobenzene.