When a bromine atom gains an electron, it becomes a bromide ion with a charge of -1. This extra electron fills the outer electron shell of the bromine atom, giving it a full set of electrons and making it stable.
i was hoping somebody else would noo arg!! my science teacher mss Edwards is asking me al these questions and i cant figure them out at all .. of well let me no guyz love hollie x Potassium bromide (KBr) is water soluble, when met with water it will dissolve. The dissolution of KBr in water is an endothermic reaction, the enthalpy change is about +19.8 Kj/mol. Does anyone know why the solution process occurs even though the enthalpy is a relatively high positive number which should mean weaker bonds?
When a bromine atom gains an electron to form the bromide ion (Br-), it becomes negatively charged. The added electron gives the ion a full outer shell of electrons, making it stable. The bromide ion will be attracted to positively charged ions or molecules.
When bromine and sodium combine, they react to form sodium bromide. This is a salt that is water soluble and a common source of bromine in various chemical applications. The reaction between bromine and sodium is a redox reaction where sodium loses an electron to bromine.
Potassium (K) has 1 valence electron which is loses to become K^+. Fluorine has 7 valence electrons and picks up the 1 electron lost by K, and it becomes F^-. They attract each other to become KF.
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Bromine gains an electron to achieve a stable electron configuration and forms the bromide ion with a negative charge. This process is called reduction as bromine is gaining an electron.
Bromine loses an electron and forms a bromide ion by gaining one electron in the reaction with sodium. Sodium donates its electron to bromine, making the bromine atom gain one electron and become a bromide ion during the reaction.
In the reaction, bromine gains an electron and forms a bromide ion (Br-). This results in a decrease in the oxidation state of the bromine atom from 0 to -1.
In the reaction, bromine gains an electron to become a bromide ion with a negative charge. This process is known as reduction because the bromine atom is gaining an electron, which results in a decrease in its oxidation state.
When potassium is allowed to burn in bromine vapor, a vigorous reaction occurs, resulting in the formation of potassium bromide. The reaction produces a bright light and heat. Potassium bromide is a stable, white crystalline compound.
In the reaction between bromine and sodium, bromine gains an electron to form the bromide ion (Br^-). This process is known as reduction, where bromine undergoes a gain of electrons and a decrease in oxidation state.
a dipole in induced.
When a bromine atom gains an electron, it becomes a bromide ion with a charge of -1. This extra electron fills the outer electron shell of the bromine atom, giving it a full set of electrons and making it stable.
i was hoping somebody else would noo arg!! my science teacher mss Edwards is asking me al these questions and i cant figure them out at all .. of well let me no guyz love hollie x Potassium bromide (KBr) is water soluble, when met with water it will dissolve. The dissolution of KBr in water is an endothermic reaction, the enthalpy change is about +19.8 Kj/mol. Does anyone know why the solution process occurs even though the enthalpy is a relatively high positive number which should mean weaker bonds?
When a bromine atom gains an electron to form the bromide ion (Br-), it becomes negatively charged. The added electron gives the ion a full outer shell of electrons, making it stable. The bromide ion will be attracted to positively charged ions or molecules.
When bromine and sodium combine, they react to form sodium bromide. This is a salt that is water soluble and a common source of bromine in various chemical applications. The reaction between bromine and sodium is a redox reaction where sodium loses an electron to bromine.