225 g
The density of water is 1000 kg/m3 1,000 kg/lThe density of ethanol 789 kg/m3 0,789 kg/lThe answer is 1 liter of water =)
To find the moles of alcohol in 70 cl of Jack Daniel's at 40% ABV (alcohol by volume), first convert the volume to liters: 70 cl = 0.7 L. Since 40% ABV means that 40% of the liquid is pure ethanol, the volume of ethanol is 0.7 L × 0.40 = 0.28 L. The density of ethanol is approximately 0.789 g/mL, so the mass of ethanol is 0.28 L × 789 g/L = 220.92 g. Finally, to find the moles, divide the mass by the molar mass of ethanol (approximately 46.07 g/mol): 220.92 g ÷ 46.07 g/mol ≈ 4.79 moles of ethanol.
the correct density numbers are the following water= 0.9982 g/mL Toluene= .8669 g/mL Clorofomo 1.4832 g/mL Ethanol= .789 g/mL
In the CGS system, the relative density of alcohol would be expressed as a dimensionless quantity. In the SI system, the relative density of alcohol is generally expressed in kg/m^3, which represents the ratio of the density of alcohol to the density of water at a specified temperature.
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Preparation of PPM level standards of ethanol in waterUse the absolute alcohol to prepare the stock solutions of known concentration say for example: 100 ml of 1 g/L of ethanol solution1 g/L is equal to 1000 mg/L which is 1000 ppm. Otherwise the concentration of the 100 ml stock solution is 1000 ppm.Next step: Perform serial dilution procedure to prepare the required ppm level of ethanol standards. For performing the serial dilution, u have to convert the weight of ethanol into volume by dividing the weight by density of ethanol. Density of ethanol = 789 kg/cu.m or 789 g/L.
.789 g/cm cubed
in 218 890 789 653 997 years from now
You cannot calculate the density of a complex fluid like the mix of water, ethanol and sugar by a simple weighted average. Here are some estimations. The density of wine is close to that of water, dry wine is less, sweet wine is higher. Water has a density of 1.000 Kg/L Ethanol has a density of 0.789 Kg/L Sugar has a density of 1.587 Kg/L So wine with 13% alcohol by volume and 0.5% sugar by volume has a density of 0.13*789 + 0.005*1587 + 0.865*1000 = 975.5 Kg/L
When 1 liter of ethanol (C2H5OH) is burned, it produces about 1.5 kilograms of carbon dioxide (CO2). This calculation is based on the complete combustion of ethanol, which releases approximately 3.0 kilograms of CO2 for every kilogram of ethanol burned. Given that 1 liter of ethanol weighs about 789 grams, this results in the release of CO2 from the carbon content in the fuel.
789 x 789 = 622521.
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