Hydrogen is oxidized because an electron is removed from it.
Not a lot. If the carbon was part of an unsaturated fat, it may break double bonds to join the fat (this is a test for unsaturation; by measuring how much iodine is absorbed we know how unsaturated the fat is). Otherwise, iodine is quite unreactive when introduced to carbon.
Often refered to by its simpler name, hydrogen iodide, the symbol is HI.
Ethanol undergoes haloform reaction when treated with halogen (like iodine or chlorine) in the presence of a base such as sodium hydroxide. This reaction involves the oxidation of the methyl group in ethanol to form a carbonyl compound, followed by halogenation and subsequent cleavage of the carbon framework to yield haloform compounds like chloroform or iodoform.
Unlike the other 3 binary acids comprised of one hydrogen atom and one halogen atom (HF, HCl, and HBr), the bond between hydrogen and iodine would be nonpolar, based on their electronegativity values on the Pauling Scale. Since nonpolar covalent bonds exist when the difference in electronegativity is below 0.5, the H---I bond ought to be considered nonpolar, since the difference is only 0.4.
When Iodine solid reacts with this alkene in presence of ethanol 1,2-diiodo-3-ethyl penman is produced stereo chemistry of produced compound shows a significant role for determining the properties of product.
oxidized
The conversion of salicylamide to iodosalicylamide involves the substitution of a hydrogen atom with an iodine atom in the presence of an iodine-containing reagent. This reaction is known as an iodination reaction.
The mechanism of iodination of salicylamide involves the substitution of a hydrogen atom on the benzene ring with an iodine atom. This reaction is typically carried out using iodine and an oxidizing agent, such as hydrogen peroxide, in the presence of a catalyst, such as a base or a metal ion. The iodine atom replaces the hydrogen atom, resulting in the formation of iodosalicylamide.
When ethanol reacts with iodine, it forms a yellow-brown solution due to the formation of iodoethane and hydrogen iodide. The reaction is a substitution reaction where iodine replaces a hydrogen atom in ethanol.
The mechanism involved in the iodination of salicylamide typically involves the substitution of a hydrogen atom on the benzene ring of salicylamide with an iodine atom. This reaction is usually carried out using iodine and an oxidizing agent, such as hydrogen peroxide, in the presence of an acid catalyst. The iodine atom replaces the hydrogen atom, resulting in the formation of iodosalicylamide.
Iodine and cyclooctene can undergo a substitution reaction in the presence of a Lewis acid catalyst to form iodocyclooctane. The iodine atom replaces one of the hydrogen atoms on the cyclooctene molecule, resulting in the formation of a new iodocyclooctane compound.
Iodination of alkanes is typically irreversible because once the iodine atom undergoes a substitution reaction with a hydrogen in the alkane, a strong C-I bond is formed making it difficult to reverse the reaction. Additionally, the reaction conditions usually do not favor the removal of the iodine atom from the alkane.
Hydrogen iodide is made by combining hydrogen gas and iodine vapor in a reaction vessel under controlled conditions. The reaction forms hydrogen iodide gas, which can be further purified and isolated through various methods such as fractional distillation.
the reactant that has the atom that gets oxidized
Tertiary alcohols are not oxidized by chromic acid because they do not have any hydrogen atoms on the carbon atom that bears the hydroxyl group. This lack of hydrogen atoms prevents the formation of a stable intermediate that is necessary for the oxidation reaction to occur.
The formula for hydrogen iodide is HI. It is a binary compound consisting of one hydrogen atom and one iodine atom.
Not a lot. If the carbon was part of an unsaturated fat, it may break double bonds to join the fat (this is a test for unsaturation; by measuring how much iodine is absorbed we know how unsaturated the fat is). Otherwise, iodine is quite unreactive when introduced to carbon.