Fe + S2 ---> FeS2
NH3 + HCl ----> NH4Cl
Na2S + Hg(NO3)2 -> 2Na(NO3) + HgS
iron(II) sulfide + sulfuric acid --> hydrogen sulfide + iron(II) sulfate FeS + H2SO4 --> H2S + FeSO4
B2S3(s) + 6 H2O (l) ---> 3 H2S(g) + 2H3BO3(aq)
Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g).
Ag2S3 + H2-------> Ag + H2S ( Write Out) Ag2S3 + 3H2-------> 2Ag + 3H2S ( Balanced) Reaction= single replacment
NaS2 is an unbalanced equation. It would need to be Na2S to be a balanced equation (two sodium, one sulfide). Na2S is Sodium Sulfide.
NH3 + HCl ----> NH4Cl
The chemical equation is:H2S + O2 = SO2 + H2O
Na2S + Hg(NO3)2 -> 2Na(NO3) + HgS
Na2S + Cu(NO3)2 -> 2NaNO3 + CuS
iron(II) sulfide + sulfuric acid --> hydrogen sulfide + iron(II) sulfate FeS + H2SO4 --> H2S + FeSO4
2h2s + o2 -> 2s + 2h2o
I assume a double displacement reaction. At least ideally. 2KI + CaS -> K2S + CaI2
B2S3(s) + 6 H2O (l) ---> 3 H2S(g) + 2H3BO3(aq)
The equation of the reaction is Fe + S -> FeS, and this equation is already balanced because it has one atom of each of iron and sulfur in both the reactants and the products.
Al2S3(s) + 6H2O(l) --> 2Al(OH)3(s) + 3H2S(g).