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What are correct regarding the reaction between potassium ferrocyanide and KMnO4 in acidic solution Permanganate ion is the oxidizing agent or Oxidized?
permanganate ion is an oxidising agent and is reduced.
What is the ammonium ion present in?
Ammonium ion (NH4+) is present in all ammonium salts (eg. ammonium chloride, or ammonium nitrate), and in smaller amounts in an ammonia (NH3) solution.
Which element forms an ion with the same charge as the ammonium ion?
The element hydrogen forms an ion with the same charge as the ammonium ion, which is +1. When hydrogen loses an electron, it becomes a hydrogen ion with a +1 charge, just like the ammonium ion.
The subscript of ammonium in a compound formed between ammonium and phosphate ion is?
The subscript of ammonium in a compound formed between ammonium and phosphate ion is 3, to balance the charge of the phosphate ion (PO₄³⁻). This compound is called ammonium phosphate (NH₄)₃PO₄.
What is the formula for ammonium iodide?
The formula for ammonium iodide is NH4I. It is composed of one ammonium ion (NH4+) and one iodide ion (I-).
What is used to test for reducing and oxidising agents?
When some substances are oxidised or reduced, there is a colour change.Testing for a reducing agent:An oxidising agent is a substance that causes another substance to be oxidised & is itself reduced. Acidified potassium manganate (VII) is an example of one. While it oxidises other substances, the manganate ion is reduced (because the oxidation state decreases showing that reduction is occuring) :MnO4- --> Mn2+oxdations state:+VII+2colour:PinkColourlessSo, to see if an unknown substance is a reducing agent, add acidifies potassium manganate (VII) to see if the pink colour fades. If it does, you know the unknown substance was a reducing agent, because it caused reduction.Testing for an oxidising agent:A reducing agent is a substance which causes reduction, but is oxidised itself. Potassium iodide is a powerful reducing agent. While it reduces other substances, the iodide ion is oxidised (because the oxidising state increases) resulting in a colour change:2I- -->I2Oxidising state:-10 (the oxidising state of a diatomic molecule is 0)Colour:ColourlessRed-brownSo, to see if an unknown substance is an oxidising agent, add potassium iodide to see if a red-brown colour appears. If it does, you know your unknown substance is an oxidising agent because it caused a reduction
Difference between ammonium sufide and sulfite?
Ammonium sulfide is a compound with the formula (NH4)2S, formed from ammonia and hydrogen sulfide, and is used in various applications such as in analytical chemistry and as a reducing agent. On the other hand, sulfite refers to the sulfite ion, SO3^2-, or compounds containing this ion, and is commonly used as a food preservative. Sulfite can also be involved in various chemical reactions as a reducing or oxidizing agent.
Does ferrous ion act as reducing or oxidizing agent?
ferrous ion act as reducing agent as it will be oxidized into ferric
Is iodine reducing agent?
No, iodine is not a reducing agent. It is commonly used as an oxidizing agent in various chemical reactions.
Is the ammonium ion an acid or a base?
The ammonium ion is an acid.
What polyatomic ions is known as ammonium?
NH4+ ion is ammonium ion
What is ammonium ion as an element?
Ammonium is an ion not an element; the chemical formula is (NH4)+.
What is the ammonium ion?
The ammonium cation is (NH4)+.
Is ammonium permanganate ionic or covalent?
Ammonium permanganate is an ionic compound. It contains the ammonium ion (NH4+) which is a positively charged ion and the permanganate ion (MnO4-) which is a negatively charged ion.
What are correct regarding the reaction between potassium ferrocyanide and KMnO4 in acidic solution Permanganate ion is the oxidizing agent or Oxidized?
permanganate ion is an oxidising agent and is reduced.
Is ammonium sulfide a ionic?
Yes, ammonium sulfide is an ionic compound. It is composed of the ammonium ion (NH4+) and the sulfide ion (S2-), which are held together by ionic bonds formed through the transfer of electrons from the ammonium ion to the sulfide ion.
How do you write ammonium flouride?
The ammonium ion is NH4+ Fluoride is F- Therefor ammonium fluoride is NH4 F
