AgBr precipitates and in light decomposes to bromine and silver metal.
potassium bromide + fluorine --> potassium fluoride + bromide
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
ethyl magnesium bromide to propanol
CH4 + Br2 --> CH3Br + HBr
It produces Bromomethane and Hydrogen Bromide Equation: CH4 + Br2 ----> CH3Br + HBr
potassium bromide + fluorine --> potassium fluoride + bromide
Not a chemical reaction but the formation of hydrogen bromide (or hydrobromic acid, HBr) water solution.
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
A salt named potassium bromide.
This equation is:AgNO3 + KBr = AgBr(s) + KNO3Silver bromide is a white precipitate.
ethyl magnesium bromide to propanol
HBr(aq)+ NaOH(aq)---> HOH(l)+ NaBr(aq) or sodium hydro bromide and hydroxyl ions
By Wurtz reaction of ethyl bromide with sodium metal.
Well, if your talking about the reaction between sodium bromide (NaBr) and Iodine, then I don't think that it will replace bromine. Bromine is higher on the reactivity series, so if they come into contact with each other, there won't simply be any reaction
This is a double displacement reaction.
CH4 + Br2 --> CH3Br + HBr
It produces Bromomethane and Hydrogen Bromide Equation: CH4 + Br2 ----> CH3Br + HBr