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Pb+K3ClO3 does not react because on the chemical activity series, Lead (Pb) is below Potassium (K) .

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But Pb can reduce the chlorate ClO3- to give Cl- and 3 PbO, because Pb2+ (as oxide) is lower than chlorate in the reactivity scale of oxidants, the same as saying: Pb higher than Cl- as reductant.

3Pb(s) + ClO3-(aq) --> 3 PbO(s) + Cl-(aq)

(K+(aq) is tribened, not taking part in reaction, unchanged)

Remember that this is a heterogenous reaction (Liq./Sol.), taking place only at the inter-surface. This reaction will stop when all (free) Pb-metal surface is covered by lead oxide deposited on that. Then there is no contact for chlorate ions to the free Pb-surface.

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What does lead nitrate and potassium bromide make?

Lead nitrate and potassium bromide react to form lead(II) bromide and potassium nitrate. This chemical reaction is a double displacement reaction where the cations and anions exchange partners to form the new compounds.


What happens when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube?

A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.


What is the net ionic equation of lead II nitrate with potassium bromide?

The net ionic equation for lead(II) nitrate (Pb(NO3)2) and potassium bromide (KBr) is: Pb2+ (aq) + 2Br- (aq) -> PbBr2 (s) This equation represents the formation of the insoluble salt lead(II) bromide.


What are the changes in adding potassium iodide to lead nitrate?

When potassium iodide is added to lead nitrate, a precipitation reaction occurs resulting in the formation of lead iodide, a yellow insoluble solid, and potassium nitrate, which remains in solution. This reaction can be visually identified by the formation of a yellow precipitate.


When you add lead nitrate and Potassium Iodide and filter them what is the solid?

The solid formed when adding lead nitrate and potassium iodide and filtering the mixture is lead iodide. Lead iodide is a yellow precipitate that forms by the reaction between lead nitrate and potassium iodide.

Related Questions

What does lead nitrate and potassium bromide make?

Lead nitrate and potassium bromide react to form lead(II) bromide and potassium nitrate. This chemical reaction is a double displacement reaction where the cations and anions exchange partners to form the new compounds.


What is the product Mixing lead nitrate and potassium bromide?

It is lead bromide and potassium nitrate


What kind of reaction is sodium bromide and lead nitrate is?

This is a double displacement reaction.


What happens when potassium iodide react with lead nitrate?

When potassium iodide reacts with lead nitrate, a double displacement reaction occurs. The potassium ion and the lead ion switch places to form potassium nitrate and lead iodide. This reaction results in the formation of a yellow precipitate of lead iodide.


What happens when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube?

A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.


What is the reaction of lead 2 nitrate and potassium sulfate?

When lead (II) nitrate and potassium sulfate are mixed, they will undergo a double displacement reaction. The products of this reaction are lead (II) sulfate and potassium nitrate. This can be represented by the chemical equation: Pb(NO3)2 + K2SO4 -> PbSO4 + 2KNO3.


What is the chemical reaction of a solution of lead nitrate is added to a solution of potassium sulfate?

The chemical reaction between lead nitrate (Pb(NO3)2) and potassium sulfate (K2SO4) produces solid lead sulfate (PbSO4) and potassium nitrate (KNO3) in solution. The balanced chemical equation is: Pb(NO3)2 + K2SO4 -> PbSO4(s) + 2KNO3.


When potassium iodine solution is added to a solution of lead nitrate in a test tube what will be the compound precipitate?

The compound precipitate formed when potassium iodide is added to a solution of lead nitrate is lead iodide, which is a yellow precipitate. This reaction is a double displacement reaction where the potassium ion and nitrate ion switch partners to form potassium nitrate and lead iodide.


What is the net ionic equation of lead II nitrate with potassium bromide?

The net ionic equation for lead(II) nitrate (Pb(NO3)2) and potassium bromide (KBr) is: Pb2+ (aq) + 2Br- (aq) -> PbBr2 (s) This equation represents the formation of the insoluble salt lead(II) bromide.


What does lead nitrate and potassium hydroxide?

Lead nitrate and potassium hydroxide react to form lead hydroxide and potassium nitrate. This reaction is a double displacement reaction where the positive ions switch places. Lead hydroxide is insoluble in water and forms a precipitate.


Is there any way to make lead chromate?

by the reaction of lead nitrate with potassium chromate or potassium dichromate


What are the changes in adding potassium iodide to lead nitrate?

When potassium iodide is added to lead nitrate, a precipitation reaction occurs resulting in the formation of lead iodide, a yellow insoluble solid, and potassium nitrate, which remains in solution. This reaction can be visually identified by the formation of a yellow precipitate.