Pb+K3ClO3 does not react because on the chemical activity series, Lead (Pb) is below Potassium (K) .
Added:
But Pb can reduce the chlorate ClO3- to give Cl- and 3 PbO, because Pb2+ (as oxide) is lower than chlorate in the reactivity scale of oxidants, the same as saying: Pb higher than Cl- as reductant.
3Pb(s) + ClO3-(aq) --> 3 PbO(s) + Cl-(aq)
(K+(aq) is tribened, not taking part in reaction, unchanged)
Remember that this is a heterogenous reaction (Liq./Sol.), taking place only at the inter-surface. This reaction will stop when all (free) Pb-metal surface is covered by lead oxide deposited on that. Then there is no contact for chlorate ions to the free Pb-surface.
Potassium chromate plus lead plus chloride in a balanced equation is given as .Pb(NO3)2 (aq) + K2CrO4 (aq) >> PbCrO4(s) + 2 KNO3 (aq)
The products are lead chromate and potassium nitrate.
Pb(NO3)2 (aq) + 2KCl (aq) --> 2KNO3 (aq)+ PbCl2 (s)
Pb(NO3)2 + K2CrO4 ------> PbCrO4 + 2KNO3
The balanced equation for potassium chromate and lead (II) acetate is as follows: Pb(CH3COO)2 (aq) + K2CrO4 (aq) ----> PbCrO4(s) + 2K+ (aq) + 2(CH3COO-) (aq)
Pb(NO3)2 + 2 KBr = PbBr2 + 2 KNO3
The lead bromide has a low solubility in water.
Pb + K2Cr2O7 ---> PbCr2O7 + 2K
K2CrO4
lead nitrate + potassium bromide --> lead bromide + potassium nitrate
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
The chemical reaction is: 2 (K+ + Br-)(aq) + (Pb2+ + 2 [NO-3])(aq)----------------- 2 (K+ + [NO-3]) + PbBr2(s)
lead iodide crystals.. check this site out for the reaction answer.. http://en.wikipedia.org/wiki/Lead(II)_iodide
2KI+Pb(NO(3))(2) yields 2KNO(3)+PbI(2). You basically get potassium nitrate and lead (II) iodide when you react potassium iodide and lead nitrate dissolved in solution.
lead nitrate + potassium bromide --> lead bromide + potassium nitrate
It is lead bromide and potassium nitrate
Lead nitrate + potassium sulfate ---> Lead sulfate + Potassium nitrate
This is a double displacement reaction.
In the reaction: Lead (Ⅱ) Nitrate + Potassium Iodide → Potassium Nitrate + Lead (Ⅱ) Iodide.. all nitrates are soluble and lead(ii)iodide is insoluble.
by the reaction of lead nitrate with potassium chromate or potassium dichromate
The chemical reaction is: 2 (K+ + Br-)(aq) + (Pb2+ + 2 [NO-3])(aq)----------------- 2 (K+ + [NO-3]) + PbBr2(s)
This is a double displacement reaction. 2KI + Pb(NO3)2 --> 2KNO3 + PbI2 Potassium iodide + Lead(II) nitrate --> Potassium nitrate + Lead(II) iodide A bright yellow precipitate will form when these two react.
It produces Potassium nitrate and Lead iodide
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
A precipitate of Lead iodide and Potassium nitrate are formed
Potassium Iodide- KI Lead Nitrate- Pb(NO3)2