2 Na + 2 LiCl = Li2 (Lithium) + 2NaCl (Table Salt)
C = 4.83 m LiClmole ratio = Xmoles = nA = soluteB = solventXA = nA___nA + nBsolution of LiCl in watersolute = LiClsolvent = water = H2Omolality = moles of solute = moles of solutekg of solvent 1.0 kg of solventAssume 1.000 kg H2O1.000 kg H2O * 1000 g * 1 mol H2O = 55.49 mol H2O1 kg 18.02 g H2OXA = nA___nA + nBSolve for nAXA( nA + nB ) = nAXAnA = XBnB = nAXAnB = nA - XAnAXAnB = nA( 1 - XA)XAnB___ = nA( 1 - XA)Plug in known amountsnA = 0.08 * 55.49 mol H2O = 4.83 mol LiCl1 - 0.08If molality = moles of solute1.0 kg of solventTHEN molality of LiCl = 4.83 mol LiCl = 4.83 m1.000 kg H2O
At No(F) + At No(Na) = 20.At No of Calcium = 20.
Using polarizing theory: Li+ has a smaller atomic radius than Na+. However they both have the same charge, +1. The Cl- is identical in both compounds, and has a large electron cloud surrounding it. Using the equation for static force: F=kq1q2/r2 where k is Coulomb's constant, q1 is the charge of the Li+ or Na+ cation, q2 is the charge of an electron in the chlorine electron cloud, and r is the distance between the chlorine electron and the Li+ or Na+ nucleus. we see that the force increases with a smaller radius r. Since the Li+ ion is smaller, the chlorine electrons are closer to the nucleus, and thus these electrons are drawn even closer to the Li+ nucleus. All together, the electrons from the chlorine in LiCl are pulled around the Li+ ion to a much further extent than they are pulled around the Na+ in NaCl. Therefore the bond in LiCl has a much more covalent character than NaCl. Bond polarity is also reduced, since the electrons are not spending all of their time around the Cl-. Since the LiCl molecules are less polar than NaCl, there are less electrostatic forces holding them together in a solid crystal lattice. Therefore the energy required to loosen the molecules from a crystal to a liquid is less for LiCl than NaCl. Finally we come to the conclusion that therefore, the melting temperature of LiCl must be lower than NaCl
Na+(aq) + C2H3O2-(aq) + Ag+(aq) + Cl-(aq) → Na+(aq) + C2H3O2-(aq) + AgCl(s) This net ionic equation represents the reaction between sodium chloride and silver acetate, forming sodium acetate and silver chloride.
Molar conductivity = the sum of the ion conductivities of cation and anion at infinite dilution, such that : This behavior was explained by Kohlraushc's law of independent migration of ions. So you can look this law up for further explanation
Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
Sodium (Na) has been reduced.
C = 4.83 m LiClmole ratio = Xmoles = nA = soluteB = solventXA = nA___nA + nBsolution of LiCl in watersolute = LiClsolvent = water = H2Omolality = moles of solute = moles of solutekg of solvent 1.0 kg of solventAssume 1.000 kg H2O1.000 kg H2O * 1000 g * 1 mol H2O = 55.49 mol H2O1 kg 18.02 g H2OXA = nA___nA + nBSolve for nAXA( nA + nB ) = nAXAnA = XBnB = nAXAnB = nA - XAnAXAnB = nA( 1 - XA)XAnB___ = nA( 1 - XA)Plug in known amountsnA = 0.08 * 55.49 mol H2O = 4.83 mol LiCl1 - 0.08If molality = moles of solute1.0 kg of solventTHEN molality of LiCl = 4.83 mol LiCl = 4.83 m1.000 kg H2O
2NaH2 + O2 yields 2Na + 2H2O
Sodium (Na)
This is the chemical formula of sodium chloride.
P + Na(OH) + H20 = NaH2PO2 + PH3
it goes from +1 to 0
Na+ and Cl- are spectator ions.
No. There are 2 Na atoms being added to 1 Cl atom.
At No(F) + At No(Na) = 20.At No of Calcium = 20.
Na+is bigger