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First calculate the molar mass of the potassium chlorate
KClO3 K is 39.1, Cl is 35.45 and O is 16 x 3 =48
The molar mass for one mol is 122.55g/mol
The percent composition is the part the oxygen contributed divided by the total molar mass times 100(to convert a decimal to a percent)
48/122.55 x 100 is 39.167%
Potassium Chlorate is 39.167 percent oxygen
What else can I help you with?
How do you calculate the theoretical mass percentage of oxygen in potassium chlorate?
To calculate the theoretical mass percentage of oxygen in potassium chlorate, you would use the formula weight of oxygen divided by the formula weight of the compound (potassium chlorate) multiplied by 100. The formula weight of oxygen is 16.00 g/mol and the formula weight of potassium chlorate (KClO3) is 122.55 g/mol. So, (16.00 g/mol / 122.55 g/mol) * 100 = 13.06%.
How oxygen is prepared in lab using potassium chlorate?
Oxygen can be prepared in the lab by heating potassium chlorate. When heated, potassium chlorate decomposes to form oxygen gas and potassium chloride residue as a byproduct. This reaction is commonly used in the laboratory setting to generate oxygen for various experiments and processes.
What elements does potassium chlorate contain?
Potassium chlorate is a compound containing potassium, chlorine, and oxygen atoms. It's molecular formula is KClO3.
What does potassium chlorate decompose into?
When heated, potassium chlorate decomposes into potassium chloride and oxygen gas. This reaction is often used in chemistry demonstrations to generate oxygen gas.
Potassium chlorate decomposes to?
Potassium chlorate decomposes to form potassium chloride and oxygen gas when heated. This reaction is commonly used in chemistry demonstrations and in the production of oxygen gas in the lab.
How do you calculate the theoretical mass percentage of oxygen in potassium chlorate?
To calculate the theoretical mass percentage of oxygen in potassium chlorate, you would use the formula weight of oxygen divided by the formula weight of the compound (potassium chlorate) multiplied by 100. The formula weight of oxygen is 16.00 g/mol and the formula weight of potassium chlorate (KClO3) is 122.55 g/mol. So, (16.00 g/mol / 122.55 g/mol) * 100 = 13.06%.
What elements is potassium chlorate a compound of?
Potassium chlorate is KClO3 and it consists of potassium, chlorine and oxygen.
How many grams of potassium chlorate would be produced by reacting 500 grams of potassium chlorate with oxygen gas?
The reaction between potassium chlorate and oxygen gas generates potassium chloride and oxygen gas. Therefore, the amount of potassium chlorate produced from the reaction is equal to the amount of potassium chlorate that was used, which is 500 grams.
How many oxygen atoms are there in one molecule of potassium chlorate?
Potassium chlorate (KClO3) has 3 oxygen atoms.
What the conclusion of composition of potassium chlorate?
we can know that potassium chlorate is very poisonous.
How many grams of potassium chlorate will produce 112.5g of oxygen?
To calculate the amount of potassium chlorate needed to produce 112.5g of oxygen, you first need to determine the molar ratio between potassium chlorate and oxygen. Then, use this ratio to convert the grams of oxygen to grams of potassium chlorate using the molar masses of each compound.
What element is both found in potassium chlorate and zinc nitrate?
Oxygen is present in both zinc nitrate and potassium chlorate. Potassium chlorate = KClO3 and zinc nitrate = ZnNO3 .
How oxygen is prepared in lab using potassium chlorate?
Oxygen can be prepared in the lab by heating potassium chlorate. When heated, potassium chlorate decomposes to form oxygen gas and potassium chloride residue as a byproduct. This reaction is commonly used in the laboratory setting to generate oxygen for various experiments and processes.
What is the gas evolved in heated potassium chlorate?
Oxygen gas is evolved when potassium chlorate is heated. The thermal decomposition of potassium chlorate releases oxygen gas, leaving behind potassium chloride as a residue. This reaction is commonly used in oxygen-generating experiments and processes.
How much potassium chlorate should be heated to produce 2.24 L of oxygen at NTP?
1 mole of potassium chlorate produces 3 moles of oxygen gas when heated, or 1 mole of potassium chlorate produces 1.344 L of oxygen gas at NTP. To produce 2.24 L of oxygen gas, you would need about 1.67 moles of potassium chlorate.
How many moles of potassium chlorate are needed to give 1.50 moles of oxygen?
The answer is 1 mole potassium chlorate.
What is the formula for converting potassium chlorate into oxygen?
The chemical equation for converting potassium chlorate (KClO3) into oxygen (O2) is: 2KClO3 (s) -> 2KCl (s) + 3O2 (g). When heated, potassium chlorate decomposes into potassium chloride and oxygen gas.
