Pb(CH3CO2)2 (aq) + 2KCr (aq) --> PbCr2 (s) + 2KCH3CO2
Potassium Chromate is:
K2CrO4
Pb(C2H3O2) + K2CrO4 > PbCrO4
Combine aqueous solutions of copper(II) chloride and potassium chromate to get a precipitate of copper(II) chromate.
MnCrO4 is manganese(II) chromate
Lead ions = Pb2+Chromate ions = CrO4-2Compound they form is Lead(II) chromate = PbCrO4
Pb2+(aq)+2Cl-(aq)→PbCl2(s)
Pb(C2H3O2) + K2CrO4 > PbCrO4
Lead (II) Dichromate
Combine aqueous solutions of copper(II) chloride and potassium chromate to get a precipitate of copper(II) chromate.
Yes. PbCl2 (s)
Lead ions = Pb2+Chromate ions = CrO4-2Compound they form is Lead(II) chromate = PbCrO4
Lead(II) Chromate = PbCrO4
Yes; lead(II) chloride is very low soluble in water.
MnCrO4 is manganese(II) chromate
Lead ions = Pb2+Chromate ions = CrO4-2Compound they form is Lead(II) chromate = PbCrO4
PbCrO4
Pb2+(aq)+2Cl-(aq)→PbCl2(s)
You probably mean lead chromate since you have mentioned an oxidation state of 2+ for the lead ion and the chromate ion has an oxidation state of 2-. Lead chromate is yellow. Please see the link.