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The formula for it is CaCO3 Therefore it is fairly simple to work out.

Ca is 40

C is 12

O is 16 x3 48

Add them all up 100

hope this helps :)

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How do you convert 50 g of calcium carbonate into moles?

1. Calculate formula massCalcium carbonate has chemical formula CaCO3.Its formula mass is 40.1 + 12.0 + 3(16.0) = 100.12. Apply formula to calculate number of moles of CaCO3Amount of CaCO3= mass/formula mass= 50/100.1= 0.50mol


How many milligrams of calcium are present in 500 mg tablet of calcium carbonate?

The formula for calcium carbonate is CaCO3, and it has a gram formula mass of 100.09. The formula shows that each formula mass contains one calcium atom, which has a gram atomic mass of 40.08. Therefore, the mass fraction of calcium in calcium carbonate is 40.08/100.09, so that a 500 mg tablet of calcium carbonate contains 200 mg of calcium, to the justified number of significant digits.


What information is needed to calculate the mass of calcium oxide that can be produced frrom 4.7 kg of calcium carbonate?

To calculate the mass of calcium oxide produced from 4.7 kg of calcium carbonate, you need to know the molar mass of calcium carbonate (CaCO3) and calcium oxide (CaO), as well as the stoichiometry of the reaction between these two compounds. This information will allow you to determine the theoretical yield of calcium oxide that can be obtained from the given mass of calcium carbonate.


What is the formula mass of CaCO3?

The formula mass of CaCO3 (calcium carbonate) is calculated by adding the atomic masses of each individual element in the compound. The atomic mass of calcium (Ca) is 40.08, of carbon (C) is 12.01, and of oxygen (O) is 16. The formula mass of CaCO3 is therefore 40.08 + (12.01 x 1) + (16 x 3) = 100.09 g/mol.


What is the mass in grams of 0.250 mol of the common antacid calcium carbonate?

The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. To find the mass of 0.250 mol of calcium carbonate, you would multiply the number of moles by the molar mass: 0.250 mol x 100.09 g/mol = 25.02 grams of calcium carbonate.

Related Questions

How many moles are there in 200 grams of Calcium Carbonate?

For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.


How do you convert 50 g of calcium carbonate into moles?

1. Calculate formula massCalcium carbonate has chemical formula CaCO3.Its formula mass is 40.1 + 12.0 + 3(16.0) = 100.12. Apply formula to calculate number of moles of CaCO3Amount of CaCO3= mass/formula mass= 50/100.1= 0.50mol


What is the relative molecular mass of caco3?

The relative molecular mass of CaCO3 (calcium carbonate) is approximately 100.09 g/mol.


How many milligrams of calcium are present in 500 mg tablet of calcium carbonate?

The formula for calcium carbonate is CaCO3, and it has a gram formula mass of 100.09. The formula shows that each formula mass contains one calcium atom, which has a gram atomic mass of 40.08. Therefore, the mass fraction of calcium in calcium carbonate is 40.08/100.09, so that a 500 mg tablet of calcium carbonate contains 200 mg of calcium, to the justified number of significant digits.


How many moles of calcium carbonate are in 1.719 grams?

Calcium carbonate, CaCO3 has formula mass of 40.1+12.0+3(16.0) = 100.1Amount of CaCO3 = 1.719/100.1 = 0.0172molThere are 0.0172 moles of calcium carbonate in a 1.719 gram pure sample.


What drugs that involve with the mass of calcium carbonate?

Many antacids and calcium supplements contain calcium carbonate.


Percent calcium ion in calcium carbonate?

Calcium carbonate (CaCO3) consists of one calcium ion (Ca2+) and one carbonate ion (CO3^2-). Therefore, the percentage of calcium ions in calcium carbonate is calculated as: (Atomic mass of calcium / Molecular mass of calcium carbonate) x 100 = (40.08 / 100.09) x 100 = 40.02% Therefore, calcium ions make up approximately 40.02% of the total mass of calcium carbonate.


What is the percent mass of calcium in a calcium supplement if 1.35-g of calcium carbonate is extracted from a 2.36-g pill?

The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. To calculate the percent mass of calcium, you need to divide the molar mass of calcium (40.08 g/mol) by the molar mass of calcium carbonate. This gives you a result of 0.4006, meaning that calcium constitutes approximately 40.06% of the mass of calcium carbonate.


What is the mass of 0.5 moles of calcium carbonate?

The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, the mass of 0.5 moles of calcium carbonate would be 0.5 mol x 100.09 g/mol = 50.045 grams.


What information is needed to calculate the mass of calcium oxide that can be produced frrom 4.7 kg of calcium carbonate?

To calculate the mass of calcium oxide produced from 4.7 kg of calcium carbonate, you need to know the molar mass of calcium carbonate (CaCO3) and calcium oxide (CaO), as well as the stoichiometry of the reaction between these two compounds. This information will allow you to determine the theoretical yield of calcium oxide that can be obtained from the given mass of calcium carbonate.


What is the difference between the masses of sodium bicarbonate and calcium carbonate?

The mass of sodium bicarbonate (NaHCO3) is 84 grams/mol, while the mass of calcium carbonate (CaCO3) is 100 grams/mol. Therefore, calcium carbonate has a higher molecular mass compared to sodium bicarbonate.


What is mass of calcium carbonate is to be decomposed to obtain 4.4 gram of carbon dioxide in the reaction caco3-cao plus o2?

The equation given shows that each formula mass of calcium carbonate produces one formula mass of CO2. The gram formula masses of calcium carbonate and carbon dioxide are 100.09 and 44.01 respectively. Therefore, to produce 4.4 grams of carbon dioxide, 4.4(100.09/44.01), or 10 grams of calcium carbonate, to the justified number of significant digits, are needed.