0
So the since its SN1 it would be a two step process:
1st step is the dissociation of the Cl so you get your carbocation.
The second steps involves the Cl attaching to the NA+ and the I attaches with the carbocation.
The acetone is not soluble with the NaCl so at the end of the reaction you'll have some precipiate from it.
What else can I help you with?
Balance chemical equation of sodium chloride plus potassium iodide?
The balanced chemical equation for the reaction between sodium chloride (NaCl) and potassium iodide (KI) is: 2NaCl + KI → NaI + KCl. This equation ensures that there is the same number of each type of atom on both sides of the reaction.
Molecular equation of NaI Cl2?
By this, I assume you mean, the chemical reaction. If this is the case, the answer is 2I +2NaCl
What would be the effect of carrying out the sodium iodide in acetone reaction with the alkyhalides using an iodide solution half as concentrated?
A reaction with alkyl halides in NaI with acetone is by the Sn2 mechanism. The rate for an Sn2 mechanism is directly proportional to the concentration of the nucleophile: rate = k[nucleophile][alkylhalide] If the iodine solution (the nucleophile) is half as concentrated, then the rate will also be halved. rate = k [nucleophile]/2 [alkyl halide]
What is the balanced reaction equation between sodium thiosulfate and molecular iodine?
2KI+MnO_2+3H_2 SO_4→2I+2KHSO_4+MnSO_4+2H_2 O
Sodium hypochlorite reaction with potassium iodide?
When sodium hypochlorite reacts with potassium iodide, the following reaction takes place: 2 NaOCl + 2 KI -> 2 NaI + 2 KCl + O2 This reaction forms sodium iodide, potassium chloride, and oxygen gas as products.
How can you tell sodium chloride from sodium iodide?
NaI is solubale in acetone while NaCl is not soluable
Balance chemical equation of sodium chloride plus potassium iodide?
The balanced chemical equation for the reaction between sodium chloride (NaCl) and potassium iodide (KI) is: 2NaCl + KI → NaI + KCl. This equation ensures that there is the same number of each type of atom on both sides of the reaction.
Molecular equation of NaI Cl2?
By this, I assume you mean, the chemical reaction. If this is the case, the answer is 2I +2NaCl
What is the reaction of sodium hypochlorite and potassium iodide?
When sodium hypochlorite (NaClO) reacts with potassium iodide (KI), it forms potassium chloride (KCl), sodium iodide (NaI), and elemental iodine (I2). This reaction can be represented by the equation: 3NaClO + 2KI → KCl + NaCl + NaI + I2.
What would be the major product if 1-bromo-3-chloropropane reacted with one equivalent of NaI in acetone?
A major product of the reaction between 1-bromo-3-chloropropane and one equivalent of Nal in acetone is 1-iodo-3-chloropropane. A minor product is 1-bromo-3-iodopropane.
What are the differences between NaCl and NaI?
Sodium chloride (NaCl) and sodium iodide (NaI) are both ionic compounds, with NaCl being composed of sodium ions and chloride ions, and NaI being composed of sodium ions and iodide ions. The main difference between the two is the anion present in each compound, chloride in NaCl and iodide in NaI, which affects their solubility, reactivity, and physical properties. Sodium iodide tends to be more reactive and soluble in polar solvents compared to sodium chloride.
What is ionic equation for sodium chloride plus potassium iodide?
Sodium and chlorine react with each other to produce sodium chloride, or table salt:2Na + Cl2 --> 2NaCl
What is the equation clearly showing the stereochemistry of the starting material and the product for the reaction of 2-bromobutane with sodium iodide in acetone?
2-bromobutane undergoes an SN2 reaction with sodium iodide in acetone, resulting in the substitution of the bromine atom with an iodine atom. The stereochemistry of the product is inversion of configuration, meaning the product is the opposite enantiomer of the starting material. The equation for this reaction can be represented as: (R)-2-bromobutane + NaI → (S)-2-iodobutane + NaBr
What would be the effect of carrying out the sodium iodide in acetone reaction with the alkyhalides using an iodide solution half as concentrated?
A reaction with alkyl halides in NaI with acetone is by the Sn2 mechanism. The rate for an Sn2 mechanism is directly proportional to the concentration of the nucleophile: rate = k[nucleophile][alkylhalide] If the iodine solution (the nucleophile) is half as concentrated, then the rate will also be halved. rate = k [nucleophile]/2 [alkyl halide]
Sodium nitrate plus potassium iodide?
When sodium nitrate (NaNO3) reacts with potassium iodide (KI), it forms sodium iodide (NaI) and potassium nitrate (KNO3). This reaction is a double replacement reaction, where the positive ions from each compound switch places. The chemical equation for this reaction is: NaNO3 + KI → NaI + KNO3.
What is the balanced reaction equation between sodium thiosulfate and molecular iodine?
2KI+MnO_2+3H_2 SO_4→2I+2KHSO_4+MnSO_4+2H_2 O
Complete the balance of Br2 plus NaI?
The balanced chemical equation for the reaction between Br₂ and NaI is: Br₂ + 2NaI -> 2NaBr + I₂ In this reaction, two moles of sodium iodide (NaI) react with one mole of bromine (Br₂) to form two moles of sodium bromide (NaBr) and one mole of iodine (I₂).
