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Since the charge of Mg^2+ ion is 2+ and Cl^- ion has a charge of 1-, each Mg^2+ ion will combine with 2 Cl^- ions to form MgCl2. Therefore, for 0.25 moles of Mg^2+ ions, you will need 0.50 moles of Cl^- ions for complete combination.
mg and cl are element abrieviations. most common in chemistry. mg is magnesium and cl is chlorine. you will find them on a periodic table where elements are graphed depending on atomic mass and number, also buy there rate of reaction.
Mg(s) + 3/2 O2(g) + C(s) ----> MgCO3(s)
Magnesium chloride has no overall charge because magnesium, a metal, has a +2 charge, while chloride, a nonmetal, has a -1 charge. When magnesium (Mg) donates two electrons to chlorine (Cl), each forms a stable ion (Mg²⁺ and Cl⁻) resulting in a neutral compound.
Mg and F is most likely to form an ionic compound because magnesium (Mg) has a +2 charge and fluorine (F) has a -1 charge, leading to a strong attraction between the two. Oxygen (O) and chlorine (Cl) also form ionic compounds, but the attraction between Mg and F is stronger due to their larger difference in electronegativity.
In one formula unit of MgCl2, there is one atom of magnesium (Mg) and two atoms of chlorine (Cl).
From the given elements, Mg has the largest atomic radius, hence the size.
MgCl2 has the largest formula mass among the given compounds. This is because the formula mass of a compound is the sum of the atomic masses of all the atoms in a formula unit, and magnesium (Mg) has a greater atomic mass than lithium (Li), sodium (Na), and potassium (K).
From LArgest to smallest it is Br, Mg, Na, Cl, Be.... This is because of ionization the concept is realitivly simple as you go to the right of the peroidic table they do not want to loose there electrons and the attraction of the electrons to the nucleus is greater therefore making the atoms smaller as you go to the right.
Since the charge of Mg^2+ ion is 2+ and Cl^- ion has a charge of 1-, each Mg^2+ ion will combine with 2 Cl^- ions to form MgCl2. Therefore, for 0.25 moles of Mg^2+ ions, you will need 0.50 moles of Cl^- ions for complete combination.
Ionic- the difference in electronegativity is high (Mg 1.31, Cl 3.16)
From greatest to least tendency to accept an electron, they are F, O, C, Li, and Be.
Representative elements belong to s and p block. The elements are Sodium (Na), Magnesium (Mg) and chlorine (Cl)
The high difference in electronegativity between Mg and Cl, and the fact that Mg is a metal and Cl is a non-metal, means that it's an ionic bond. Magnesium has two valence electrons; one chlorine takes one of them, another chlorine takes the other. The formula is therefore MgCl2.
Sodium (Na) is the largest element among Mg (magnesium), S (sulfur), Na (sodium), and Cl (chlorine) when comparing their atomic radii. Sodium has the largest atomic radius because it is located in the third period of the periodic table, whereas magnesium is smaller due to being in the second period.
C and N, N and H, Cl and Cl, Xe and Xe can form covalent bonds. Mg and Cl, Li and Cl, Cu and Cl, Fe and Cl can form ionic bonds due to the large difference in electronegativity. K and Cl would form an ionic bond as well.
how many mg in 20 meg potassium