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Reaction of sodium iodide with silver nitrate?
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
Molecular formula for sodium iodide and silver nitrate?
Equation: NaI + AgNO3 ----> NaNO3 + AgI
What is the ionic equation for silver nitrate to potassium iodide?
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
What is the Symbol equation for silver nitrate solution and potassium iodide?
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Silver nitrate solution is reacted with sodium iodide solution?
This is a precipitation reaction. Halides of silver are insoluble in water (except silver fluoride) whereas all nitrates are soluble in water. Sodium salts are soluble. Thus, silver iodide is the precipitate. Formula: AgNO3(aq) + NaI(aq) -> AgI(s) + NaNO3(aq)
Reaction of sodium iodide with silver nitrate?
When sodium iodide reacts with silver nitrate, a double displacement reaction occurs. The sodium ions exchange with the silver ions, forming silver iodide as a white precipitate and sodium nitrate. This reaction can be represented by the equation: 2NaI + 2AgNO3 → 2AgI + 2NaNO3
Molecular formula for sodium iodide and silver nitrate?
Equation: NaI + AgNO3 ----> NaNO3 + AgI
What is net ionic equation for sodium iodide and silver nitrate when precipitate is formed?
The net ionic equation for the reaction between sodium iodide (NaI) and silver nitrate (AgNO3) when a precipitate is formed is: 2Ag+ + 2I- -> Ag2I (s) This equation represents the formation of silver iodide (AgI) precipitate when silver cations react with iodide anions.
What is the ionic equation for silver nitrate to potassium iodide?
Potassium iodide + silver nitrate --> Silver iodide and potassium nitrate The chemical equation is: K+I- (aq) + Ag+[NO3]- (aq) --> AgI (s) + K+[NO3]- (aq)
How much sodium nitrate is produced when 1.7G of silver nitrate and 1.5G of sodium iodide is reacted?
The equation for the reaction between silver nitrate and sodium iodide is AgNO3 + NaI -> AgBr + NaNO3. The gram formula masses are 169.87 for silver nitrate, 149.89 for sodium iodide, and 84.99 for sodium nitrate. Therefore, 1.7 g of silver nitrate constitutes 1.7/169.87 or 0.010 formula mass of silver nitrate and 1.5 g of sodium iodide constitutes 1.5/149.89 or 0.010 mole of sodium iodide, to the justified number of significant digits. The reaction equation shows that the number of formula unit masses of each reactant and product are the same, so that there will be 0.85 g of sodium nitrate produced, to the justified number of significant digits.
What is the Symbol equation for silver nitrate solution and potassium iodide?
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Silver nitrate solution is reacted with sodium iodide solution?
This is a precipitation reaction. Halides of silver are insoluble in water (except silver fluoride) whereas all nitrates are soluble in water. Sodium salts are soluble. Thus, silver iodide is the precipitate. Formula: AgNO3(aq) + NaI(aq) -> AgI(s) + NaNO3(aq)
What is formed when silver nitrate is added to sodium iodine?
When aqueous solutions of silver nitrate and sodium iodide [note correct spelling] are mixed, silver iodide solid precipitates from the mixture.
What is the word and symbol equation for silver nitrate plus sodium chloride?
The word equation for silver nitrate plus sodium chloride is "silver nitrate + sodium chloride → silver chloride + sodium nitrate". The symbol equation for this reaction is "AgNO3 + NaCl → AgCl + NaNO3".
Silver nitrate as an ionic equation?
Silver nitrate + Potassium iodide ----> Silver iodide + Potassium nitrate AgNO3 + KI ----> AgI + KNO3
Silver nitrate and potassium iodide?
When silver nitrate reacts with potassium iodide, a precipitation reaction occurs where silver iodide is formed. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3. The silver iodide formed will appear as a yellow solid precipitate.
What is the molecular equation of silver nitrate and potassium iodide?
AgNO3(aq) + KI(aq) = KNO3(aq) + AgI(s) This is a classic test for halogens, and AgI precipitates down as a yellow solid.
