No.
Al+I doesn't equal Al2O3
It will yield aluminum iodide AlI3
Aluminium and iodine will give Aluminium iodide
false it forms alumminium iodide
Aluminum iodide
The formula is Al3+ + I1- ----> AlI3
180g I2
When chlorine gas is bubbled into an aqueous solution of potassium iodide, some of the iodide ions are oxidized to iodine. The iodine molecules combine with iodide ions to form brown triiodide ion, I3-. In this demonstration, the aqueous solution is above a layer of carbon tetrachloride, in which iodine is quite soluble. The beautiful violet color of iodine can be seen as the iodine dissolves in the carbon tetrachloride layer. With excess chlorine, iodine reacts to form iodine monochloride, ICl, which is ruby red. The iodine monochloride reacts further to form iodine trichloride, ICl3, which is much lighter in color, causing the solution to be decolorized.
2KI+Br2 ---->2KBr +I2
An iodide ion is an iodine atom with a −1 charge. Compounds with iodine in formal oxidation state −1 are called iodides. This can include ionic compounds such as caesium iodide or covalent compounds such as carbon tetraiodide.
you have to write... 2KI + Cl2 = 2KCl + I2
it reacts and makes aluminum iodide and hydrogen iodide (purple smoke)
KI is potassium iodide, you'd react it with something to produce iodine ions. It reacts as reducing agent
Iodide ions reacts with Chlorine to form elementary Iodine and Chloride ions
potassium iodide
Mercury reacts with iodine to form mercuric iodide. Hg(l) + I2(s) = HgI2(s)
180g I2
When chlorine gas is bubbled into an aqueous solution of potassium iodide, some of the iodide ions are oxidized to iodine. The iodine molecules combine with iodide ions to form brown triiodide ion, I3-. In this demonstration, the aqueous solution is above a layer of carbon tetrachloride, in which iodine is quite soluble. The beautiful violet color of iodine can be seen as the iodine dissolves in the carbon tetrachloride layer. With excess chlorine, iodine reacts to form iodine monochloride, ICl, which is ruby red. The iodine monochloride reacts further to form iodine trichloride, ICl3, which is much lighter in color, causing the solution to be decolorized.
it is used to indicate acidic radicals which reacts with the iodide solution.
2KI+Br2 ---->2KBr +I2
starch
Yes, it is correct.
The iodine test is used to test for starch. It reacts with starch to produce a purple blackish color.