"Solute per 100g solvent" is the unit given to solubility of a substance.
The amount of solute that can dissolve in 100g of solvent will vary as the solubility of different substances vary, but solubility also depends upon other factors such as temperature. For example the solubility for glucose at room temperature is 91g/(100ml).
molal = m = moles solute/kg solvent. Assuming water as the solvent 1 kg = 1000 g/18g/mole = 55.56 moles H2O. Moles solute = 3.71 moles. Total moles present = 55.56 + 3.71 = 59.27 moles.Mole fraction solute = 3.71/59.27 = 0.0626
I'm not sure what you mean, commercial gasoline is a blend of linear and aromatic hydrocarbons averaging about 8 carbon atoms per molecule with various additives for various purposes (e.g. keep engine clean, reduce pollutants, stabilize mixture, improve starting in cold weather). Gasoline is a solvent, but if you was a solvent for cleaning parts there are far safer ones that work as well.
Molality denotes the number of moles of solute per kilogram of solvent. The molar mass for sodium bromide is 102,9 g/mol. nNaBr= 16,6 g/ 102,9 g/mol = 0,16 moles The concentration of the solution is therfore = 0,16 moles/ 1,330 kg = 0,12 molal -While the above is true it should 0.121 molar due to significant digits (just a technicality)
To solve freezing point depression problems, you need to know the following things:-- the identity of the solute (the thing you are adding to the liquid)-- the identity of the solvent (the liquid)-- whether the solute is molecular or ionic, and if ionic, how many ions it forms-- the amount of solute (in grams or moles)-- the amount of solvent (in kilograms)-- the value of Kf of the solvent (for water, it is -1.858 K·kg/mol (or -1.858 °C molal-1)Then you use the following equation:∆T = i * Kf * mwhere ∆T is the change in the freezing point, "i" is the number of molecules or ions formed upon addition to the solvent, Kf is the freezing point depression constant, and "m" is the molality of the solution.The Kf of water for a freezing point depression is known and is equal to -1.858 °C·kg/mol (or -1.858 °C molal-1)The value of "i" has to do with what you add to the water. If you added sugar, a molecular compound the value of "i" is 1.0. If you add a ionic compound like NaCl, the value of "i" is 2.0 because for every 1 molecule of NaCl, you make 2 ions: one Na+ and one Cl- in water. For MgCl2, the value of "i" is thus 3.0 (for each MgCl2 you get one Mg2+ and two Cl- ions, so a total of 3 ions).To find "m," the molality of a solution you need to know the number of moles of solute and the number of kilograms of solvent (m = moles/kg). If you are given the number of grams of solute, the number of moles is found from the mass and the molar mass of the solute.grams of solute ÷ molar mass of solute = moles of soluteTo find the molality, just divide the moles of solute by the kilograms of solvent moles of solute ÷ kilograms solvent = molality Note: If you are given the volume of the solvent instead of the mass, use the density of the solvent to convert -- the density of water is 1 kilogram per liter)Liters of solvent * density of solvent = kilograms of solventNow just plug all the numbers into the equation at the top of the answer!
The answer is: Concentration can be expressed as grams of solute per milliliter of solvent.
The maximum amount of solute that can dissolve in a solvent at a given temperature is called the solubility limit. This limit is different for each solute-solvent combination and is usually described in terms of solubility in grams of solute per 100 grams of solvent.
The concentration of a solution can be expressed as grams of solute per milliliter of solvent. This unit of concentration is called grams per milliliter (g/mL) and is commonly used in chemistry to describe the amount of solute dissolved in a given volume of solvent.
substance with a low solubility means insoluble substance. solubility of the substance lesser than 0.1g per 100g of water
molarity
The amount of solute that can dissolve in 100g of solvent will vary as the solubility of different substances vary, but solubility also depends upon other factors such as temperature. For example the solubility for glucose at room temperature is 91g/(100ml).
The most common unit used to report the solubility of a substance is grams per liter (g/L) or moles per liter (mol/L). This unit quantifies the amount of solute that can dissolve in a given volume of solvent at a specific temperature.
This concentration is known as molality, and it is expressed as moles of solute per kilogram of solvent. To convert from moles of solute per 1000 grams of solvent to molality, you need to convert the mass of the solvent from grams to kilograms before calculating the molality.
Molality
The amount of solvent that can dissolve a given amount of solute depends on the solubility of the solute in the solvent. Solubility is a property that describes how much of a solute can dissolve in a solvent at a given temperature. It is typically expressed as grams of solute per 100 grams of solvent. It is important to note that solubility can vary for different solutes and solvents.
This concentration is called molality (now an obsolete term).
The amount of solute that can dissolve in a given amount of solvent is determined by the solubility of the solute in that solvent at a specific temperature. Solubility is expressed as grams of solute per 100 grams of solvent. By knowing the solubility, you can calculate how much solute can dissolve in the specified amount of solvent.