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Solve for the force of friction acting on a 50-kg carton sliding at 4 ms if ti stops in 3 s?
Wiki User
∙ 13y ago
F = ma; where m = 50 kg and acceleration a = v/t; where v = 4 mps and t = 3 sec.
Therefore F = ma = mv/t = 50*4/3 = 200/3 = 66.7 kg-m/sec^2 (aka Newtons).
The physics is this. Friction is the only force acting to slow the carton down from 4 mps velocity. So the F in F = ma is the friction force.
Wiki User
∙ 13y ago
Wiki User
∙ 11y ago200 N
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