Tin (IV) phosphide
Sn4+ is the symbol for Tin(IV), that is, the element tin with a oxidation state of 4.
Tin (II) Bromide.
Tin (IV) Chloride
Tin(IV) = Sn4+Chloride = Cl-Formula = SnCl4
Tin(IV) carbonate
Sn(IV)CO3
The formula for the compounds: Chromium (VI) Phosphate; Vanadium (IV) Carbonate; Tin (II) Nitrite?
The Answer To Your Question Is.... tin (IV) oxide
SnO2, if you meant (tin(IV) oxide) or tin dioxide that is
Tin (IV) phosphide
Sn4+ is the symbol for Tin(IV), that is, the element tin with a oxidation state of 4.
The systematic name of this ionic compound is Tin(IV) Selenide.
Tin (II) Bromide.
Tin (IV) nitrideTin(IV) Nitride.
Tin (IV) Chloride
Is in the Chemical Compound with the formula SnCl4, called Tin(IV) Chloride. However, Tin IV is actually just tin in a specific oxidation state. It would be better to think of it as Sn4+