8 degrees Celsius = 46.4 degrees Fahrenheit
[°F] = [°C] × 9⁄5 + 32
C = Celsius F = Fahrenheit C = (5/9)*(F-32) C = (5/9)*(8-32) = -13.3 degree Celsius
8 C = 46.4 F46.4 degreesTo convert from C to F, multiply the C temperature by 9/5 and then add 32:8oC = (9/5 x 8) + 32 = 14.4 + 32 = 46.4oF46.4 F
The conversion from deg C to Deg F is 9/5(degC) + 32. I don't understand the question as posed. 2 C = 36,5 F 8 C = 46,4 F 2 C - 8 C is -6 C = 21,2 F (if it was two degrees Celsius yesterday and the temperature dropped eight degrees overnight it would now be minus six degrees Celsius or about twenty one degrees Fahrenheit)
6° to 8°C is the same range as 42.8°to 46.4°F
°F to°C: [°C] = ([°F] − 32) × 5⁄9°C to°F: [°F] = [°C] × 1.8 + 32
-8 deg C = 17.6 deg F.
[°C] = ([°F] − 32) × 5⁄9 (-8) degrees Fahrenheit = -22.2 degrees Celsius
C = Celsius F = Fahrenheit C = (5/9)*(F-32) C = (5/9)*(8-32) = -13.3 degree Celsius
-8 C = 17.6 F
Conversion: 66°F = 18 8/9 °C ≈ 18.89°C
8oC is 46.4oF
C, d, e, f, g, a, b, c.
If you mean Fahrenheit to Celsius (Centigrade): C = (5/9)(F - 32)
8ºC = 46.4ºF
- 8 deg C = 17.6 deg F
8 C = 46.4 F46.4 degreesTo convert from C to F, multiply the C temperature by 9/5 and then add 32:8oC = (9/5 x 8) + 32 = 14.4 + 32 = 46.4oF46.4 F
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