Copper, Aluminum Chloride, and Heat.
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2Al (s) + 3CuCl2 (aq) --> 3Cu (s) + 2AlCl3 (aq)
The aluminum metal appears to be turning into copper, but it is actually just removing the metallic copper from its compound state. The Aluminum is oxidized and loses e-, becoming Al 3+ and the copper ions are reduced (they accept those e-) to form solid copper precipitate. The aluminum ions and chloride ions remain in the solution. The reaction will only occur in water and occurs because the transfer of electrons from the aluminum to the copper results in a more stable system.
The two are highly reactive when mixed in water. If you add aluminum to a water solution of copper chloride, the aluminum will be combined as aluminum chloride gas, releasing the copper into the water. The mixture will turn very hot, bubble up, and start to smoke, and the color will change from blue to dark red. ========================= The first sentence is correct, the two are highly reactive, but from there on, there are problems... There's no such thing as aluminum chloride gas. There is a gas given off, but it is hydrogen gas. The "smoke" is actually tiny droplets of water condensed from water vapor. It gets that hot. The red color is due to the formation of copper metal a Cu2+ ions are reduced to the metal as aluminum metal is oxidized. Aluminum metal has a thin coating of aluminum oxide, Al2O3, covering the surface. Even freshly scraped aluminum metal will quickly reform the passivating layer of aluminum oxide. So in many solutions, the layer of Al2O3 prevents any aluminum metal from reacting. If aluminum metal is placed in a solution of copper(II) sulfate, you will not get a reaction. No copper metal will form on the aluminum. But when placed in copper(II) chloride, aluminum will give a vigorous reaction with a lot of heat and hydrogen gas being given off. The reason is the chloride ion. In the presence of chloride ion, the Al2O3 layer dissolves forming the AlCl4^- in solution and exposing a fresh layer of aluminum metal. The aluminum metal will reduce copper(II) ions to copper metal, AND the aluminum metal will react with water very much like an alkali metal reacts with water, vigorously, with a lot of heat given off, and with the formation of hydrogen gas. Al2O3 + 8Cl- + 3H2O --> 2AlCl4^- + 6OH- Al(s) + OH- + 2H2O --> Al(OH)3(s) + H2(g) 2Al(s) + 3Cu2+ --> 2Al3+ + 3Cu(s)
No, copper chloride is a pure substance.
When silicon reacts with copper chloride, silicon will displace copper from the copper chloride solution to form silicon chloride and copper. The reaction can be represented as: 3CuCl2 + 2Si -> 2SiCl4 + 3Cu
1. 3CuCl2 (S) * 2H2O + 2Al(aq) à 2AlCl3 (aq) + 3Cu (S) + 6H2O(l) The water is in there because the reaction can only take place in water. You can remove it if it isn't what your teacher is expecting.
When copper chloride and aluminum are combined, they react to form aluminum chloride and copper metal. This is a displacement reaction where aluminum replaces copper in the chloride compound.
In a copper chloride and aluminum reaction, the aluminum oxidizes to form aluminum oxide and copper is produced. The oxygen in the copper chloride is involved in oxidizing the aluminum during the reaction, forming aluminum oxide.
The reaction between copper chloride and aluminum forms aluminum chloride and copper metal. As the copper metal is formed, it precipitates out of the solution, causing the color of the copper chloride solution to fade. This happens because the copper ions are now in the solid copper metal form instead of the solution.
When copper and chlorine ions are combined, copper chloride is formed. The copper ions (Cu²⁺) will combine with chlorine ions (Cl⁻) to form copper chloride (CuCl₂), a white solid compound.
When copper chloride solution is mixed with aluminum, a redox reaction occurs where the aluminum reduces the copper ions to form copper metal. This results in a color change from blue-green (copper chloride solution) to colorless (copper metal precipitate), giving the appearance of fading in color due to the formation of a solid copper instead of a colored solution.
Aluminum is usually combined with other elements, such as copper, silicon, magnesium, and zinc, to form various aluminum alloys. These alloys provide enhanced properties like increased strength, corrosion resistance, and improved formability compared to pure aluminum.
The balanced chemical equation for the reaction between aluminum wire and cupric chloride is 2Al + 3CuCl2 → 3Cu + 2AlCl3. In this reaction, aluminum displaces copper from cupric chloride to form copper and aluminum chloride.
The aluminum metal appears to be turning into copper, but it is actually just removing the metallic copper from its compound state. The Aluminum is oxidized and loses e-, becoming Al 3+ and the copper ions are reduced (they accept those e-) to form solid copper precipitate. The aluminum ions and chloride ions remain in the solution. The reaction will only occur in water and occurs because the transfer of electrons from the aluminum to the copper results in a more stable system.
When aluminum foil is added to copper chloride solution, a chemical reaction occurs where the aluminum replaces the copper in the compound to form aluminum chloride and copper metal. This is a chemical change because the composition of the substances is altered. The physical change that occurs is the color change of the solution from blue to greenish-brown due to the formation of copper metal.
The two are highly reactive when mixed in water. If you add aluminum to a water solution of copper chloride, the aluminum will be combined as aluminum chloride gas, releasing the copper into the water. The mixture will turn very hot, bubble up, and start to smoke, and the color will change from blue to dark red. ========================= The first sentence is correct, the two are highly reactive, but from there on, there are problems... There's no such thing as aluminum chloride gas. There is a gas given off, but it is hydrogen gas. The "smoke" is actually tiny droplets of water condensed from water vapor. It gets that hot. The red color is due to the formation of copper metal a Cu2+ ions are reduced to the metal as aluminum metal is oxidized. Aluminum metal has a thin coating of aluminum oxide, Al2O3, covering the surface. Even freshly scraped aluminum metal will quickly reform the passivating layer of aluminum oxide. So in many solutions, the layer of Al2O3 prevents any aluminum metal from reacting. If aluminum metal is placed in a solution of copper(II) sulfate, you will not get a reaction. No copper metal will form on the aluminum. But when placed in copper(II) chloride, aluminum will give a vigorous reaction with a lot of heat and hydrogen gas being given off. The reason is the chloride ion. In the presence of chloride ion, the Al2O3 layer dissolves forming the AlCl4^- in solution and exposing a fresh layer of aluminum metal. The aluminum metal will reduce copper(II) ions to copper metal, AND the aluminum metal will react with water very much like an alkali metal reacts with water, vigorously, with a lot of heat given off, and with the formation of hydrogen gas. Al2O3 + 8Cl- + 3H2O --> 2AlCl4^- + 6OH- Al(s) + OH- + 2H2O --> Al(OH)3(s) + H2(g) 2Al(s) + 3Cu2+ --> 2Al3+ + 3Cu(s)
Al(3+) + Cl(1-) = AlCl3
No, copper chloride is a pure substance.