AgNO3 + H2O ---> HNO3 + AgOH
Silver nitrate is the chemical name for the molecular compound having formula AgNO3. It is composed of silver (Ag) and a nitrate group (NO3). The reaction for its disassociation into water (H2O) is:AgNO3(s) + H20(l) <--> Ag+ (aq) + NO3-(aq) + H2O(l)
The chemical formula for silver nitrate is AgNO3.
Ammonium iodide is NH4I Silver nitrate is AgNO3
The balanced chemical equation for this reaction is: AgNO3 + NaCl -> AgCl + NaNO3 From this equation, we can see that 1 mole of AgNO3 produces 1 mole of AgCl. Since the molar mass of AgNO3 is 169.87 g/mol, 83.0 g of AgNO3 is equivalent to 0.488 moles. Therefore, 0.488 moles of AgCl will be produced.
Assuming double displacement, AgNO3 + NaOH --> AgOH + NaNO3
The reaction is:Ag2CO3 + 2 HNO3 = 2 AgNO3 + CO2 + H2O
When silver nitrate (AgNO3) is dissolved in water (H2O), it dissociates into silver ions (Ag+) and nitrate ions (NO3-). Therefore, the solution contains silver ions and nitrate ions but no hydrogen ions (H+).
When you mix AgNO3 (silver nitrate) and NH3 (ammonia), a white precipitate of AgCl (silver chloride) forms. This reaction is used to test for the presence of chloride ions in a solution, as silver chloride is insoluble in water and will precipitate out.
The product agNO3 is a chemical formula known as silver nitrate. Silver nitrate is developed by reacting silver with nitric acid. The correct formula written for silver nitrate is AgNO3, or Ag(NO3)2.
Silver nitrate is the chemical name for the molecular compound having formula AgNO3. It is composed of silver (Ag) and a nitrate group (NO3). The reaction for its disassociation into water (H2O) is:AgNO3(s) + H20(l) <--> Ag+ (aq) + NO3-(aq) + H2O(l)
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The chemical formula for silver nitrate is AgNO3.
Wrong ! ! ! ! !Silver + Nitric Acid -----> Silver Nitrate + Water + Nitrogen DioxideAg + 2 HNO3 -----> AgNO3 + H2O + NO2
The chemical formula for silver nitrate is AgNO3.
The reaction between silver carbonate (Ag2CO3) and nitric acid (HNO3) will result in the formation of silver nitrate (AgNO3), carbon dioxide (CO2), and water (H2O), as the carbonate ion reacts with the acid to form carbonic acid which then decomposes into CO2 and H2O.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of AgNO3. The molar mass of AgNO3 is 169.87 g/mol. From this, you can calculate the mass of silver (Ag) in AgNO3, which is 107.87 g/mol. Therefore, the mass of silver in 3.4g of AgNO3 is (107.87/169.87) * 3.4g.
To find the mass of silver in 3.4g of AgNO3, you need to consider the molar mass of silver nitrate (AgNO3). The molar mass of AgNO3 is 169.87 g/mol. Since the molar ratio of Ag to AgNO3 is 1:1, the mass of silver in 3.4g of AgNO3 would be 3.4g * (1/169.87) ≈ 0.02g.