The element Ar 4s2 3d10 4p6 is Krypton (Kr).
what is the element with a noble gas configuration of [ar] 4s2 3d10 4p4
what peroid is this element in
Sc
(The question is partially mis-typed)
Potassium's shortnote electron configuration is [19K] = [20Ar] 4s1 (not 5s1)
The element ending with ..., 5s1 only rubidium (37Rb) is possible: [36Kr] 5s1 (not Ar)
Argon electron configuration is [Ar] = 1s2, 2s2 2p6, 3s2 3p6, (4s0) and
Krypton electron configuration is [Kr] = 1s2, 2s2 2p6, 3s2 3p6, 4s2 4p6 4d10, (5s0)
Ca
cr
B
Selenium Se
Krypton
cr
Neutral calcium has 20 protons and 20 electrons. The first 20 atomic orbitals are filled as 1s2 2s2 2p6 3s2 3p6 4s2. The shorthand for this is [Ar] 4s2 since argon's configuration is 1s2 2s2 2p6 3s2 3p6.
Scandium forms compounds with the Sc3+ ion, losing both the 4s2 and 3d1 electrons. With no electrons in the d orbitalks its sakts are colorless.
[Ar] 3d2 4s2
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5 or [Ar] 4s2 3d10 4p5
1s 2 2s 2 2p6 3s2 3p6 4s2 or Ar 4s2 (Noble gas form) In noble gas form, you go back to the noble gas (the last group on the Periodic Table) prior to the element you are writing the configuration for. The electron configuration is the same up until that point. Then you write down the difference. In this example, the electron configuration for Argon (Ar) is 1s2 2s2 2p6 3s2 3p6. If you fill up the shells until 4s2, you get calcium. It's faster to abbreviate by saying "Ar 4s2"
[Ar] 4s2 3d1
It is [Ar] 3d1 4s2
The element scandium (atomic number 21) has the electron configuration [Ar] 3d1 4s2
The short form is [Ar] 3d1 4s2
Scandium (symbol, Sc) has 21 electrons. Its noble gas configuration is [Ar] 3d1 4s2
The electron configuration of cobalt is [Ar]3d7.4s2.
Electronic configuration of scandium: [Ar]3d1.4s2.
Long-hand version: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 Short-hand version: [Ar] 4s^2 Note: The "^" symbol means the the following number is in the form of a superscript.
Transition metal and is a d-block element. :) ~Scandium~
Bromine atom
The element is titanium and is in 4th period, group 4.
1s2 2s2 2p6 3s2 3p6 4s2 3d1