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What element is ar3d34s2?
[Ar]3d34s2 is the shorthand electron configuration for Vanadium (V).
What is element Ar 3d104s24p5?
The element with electron configuration [Ar] 3d10 4s2 4p5 is Bromine (Br), which has an atomic number of 35. It belongs to the halogen group in the periodic table.
Electronic configuration for bromine?
The electronic configuration of Bromine is [Ar] 3d10 4s2 4p5.
Noble gas notation for Zn?
[Kr] 4d10 5s2 5p2
What is the electron configuration for element kr?
The lowest atomic number ion is Se^2-. The highest atomic number ion is Sr^2+. The ones in the middle are NOT Br^- or Rb^+. However, I do not know what the correct answer for those two is.
What is the electronic configuration of Sc?
Scandium (symbol, Sc) has 21 electrons. Its noble gas configuration is [Ar] 3d1 4s2
What is the noble gas notation of scandium?
The noble gas notation of scandium is [Ar] 3d1 4s2, where [Ar] represents the electron configuration of the noble gas argon. Scandium has 21 electrons, with the electron configuration of [Ar] 3d1 4s2.
Noble gas notation for SC?
Noble gas notation for scandium (Sc) is [Ar] 3d1 4s2, where [Ar] represents the electron configuration of argon (1s2 2s2 2p6 3s2 3p6).
How do you write the shorthand electron configuration for scandium?
It is [Ar] 3d1 4s2
How do you write electronic confiriguratin of scandium?
The short form is [Ar] 3d1 4s2
What is the noble gas electron configuration of scandium?
The noble gas electron configuration of scandium is [Ar] 4s2 3d1. Scandium has 21 electrons, and the noble gas configuration represents the nearest noble gas to scandium, which is argon with 18 electrons.
What is the electron configuration of scandium (Sc)?
The electron configuration of scandium (Sc) is Ar 3d1 4s2.
What is the electron configuration of the element with 27 protons?
The electron configuration of cobalt is [Ar]3d7.4s2.
What is Ar 4s2?
Ca
What is the correct electron configuration for scandium?
The element scandium (atomic number 21) has the electron configuration [Ar] 3d1 4s2 Actually the correct configuration is [Ar] 4s2 3d1 this is because d comes after s in the ladder The ladder goes as follows: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p
Which group does the electron configuration 1s2 2s2 sp6 3s2 3p6 3d1 4s2 belongs to?
The electron configuration 1s2 2s2 sp6 3s2 3p6 3d1 4s2 belongs to the group of transition metals. It is the electron configuration of the element titanium (Ti), which is a transition metal with atomic number 22.
What is the period for the element represented by this electronic configuration Ar 4s2 3d2?
The element is titanium and is in 4th period, group 4.
