When Iron metal is dipped into a solution of copper sulfate a REDOX reaction occurs in which the Copper is reduced (gains electrons) and the iron is oxidised (loses electrons). When this happens, the iron metal becomes iron ions and the copper ions in the solution become copper metal.
Cu2+(aq) + 2e- --> Cu(s)
Fe(s) -->Fe2+(aq) + 2e-
This occurs because the iron is a more active metal than copper, and as a general rule of thumb, a more reactive metal will displace a less reactive metal from solution. This principle underlies the action of the sacrificial electrode.
When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour.Therefore, the blue colour of copper sulphate solution fades and green colour appears.
When an iron nail is dipped in the solution of copper sulphate solution , after a while the solution changes into the colour of green becoming iron sulphate and a brown substance is found on the iron nail which is copper so we get to know that the displacement reaction is produced
When copper wire is dipped in ferrous sulfate solution, a displacement reaction occurs where copper displaces iron from ferrous sulfate, forming copper sulfate and iron. As a result, the copper wire will become coated with a reddish-brown deposit of iron.
Why does the colour of copper sulphate solution change when an iron nail is dipped in it? When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour. Therefore, the blue colour of copper sulphate solution fades and green colour appears.
When an iron nail is dipped in copper sulfate solution, a displacement reaction occurs. The iron nail will displace the copper from the copper sulfate solution to form iron sulfate solution and copper metal deposits on the nail. This reaction is represented by the equation: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s).
When a iron nail is dipped into copper sulphate solution after sometime the colour is changed into pale green.
A brown layer of copper gets deposited on iron nail. This change is due to a chemical reaction between copper sulphate and iron. Also the colour of the solution changes from blue to green due to the formation of iron sulphate. This reaction can be represented by the following equation: Copper sulphate + Iron = Iron sulphate + Copper solution (CuSO4) + (Fe) = (FeSO) + (Cu)
When gold is dipped into a solution of copper sulfate, a redox reaction occurs where copper ions in the solution gain electrons and are reduced to solid copper metal. The gold does not react and remains unchanged in the solution.
When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour.Therefore, the blue colour of copper sulphate solution fades and green colour appears.
When an iron nail is dipped in the solution of copper sulphate solution , after a while the solution changes into the colour of green becoming iron sulphate and a brown substance is found on the iron nail which is copper so we get to know that the displacement reaction is produced
The copper plates out while the zinc dissolves, leaving a transparent zinc sulphate solution.
When copper wire is dipped in ferrous sulfate solution, a displacement reaction occurs where copper displaces iron from ferrous sulfate, forming copper sulfate and iron. As a result, the copper wire will become coated with a reddish-brown deposit of iron.
There would be no reaction because copper is a less reactive metal than iron. Refer to the related link for an activity series of metals.
This is due to something called a displacment reaction, during a displacment reaction one of the particals from one of the substances "swap" with another partical from the solution In the case of zink and copper sulphate solution, the copper and zink 'switch places to produce copper and a solution of zink sulphate. This is how, A + BC = B +AC
Nothing. Gold is a noble metal- it is not displaced by iron.
When aluminum is dipped into copper sulfate solution, a single displacement reaction occurs. The aluminum displaces copper in the solution, forming aluminum sulfate and copper metal. This reaction is spontaneous and the copper metal will begin to precipitate out of the solution.
When an iron nail is dipped in copper sulfate solution, a displacement reaction occurs. Iron is more reactive than copper, so it displaces copper in the solution and forms iron sulfate. This reaction causes the color change from blue (copper sulfate) to green (iron sulfate) as the copper ions are replaced by iron ions in the solution.