Burning is otherwise known as combustion. When you combust a substance you react it with oxygen and yield water and carbon dioxide. So, when you burn Potassium Chloride you get -- KCl+O2--> H2O+CO2
KCl is 'potassium chloride'.
No. Potassium chloride (KCl) is soluble in water.
I'm guessing you meant KCl or potassium chloride.
Molar mass of KCl = 74.55g/mol.ie, if you dissolve 74.55g KCl in 1litre (1000 ml) of water, it will be 1M KCl solution.If you want to make 3M KCl solution,Dissolve 3 ×74.55 = 223.65g KCl in 1litre (1000 ml) of water.If you want to make different molar solutions of KCl, just calculate as per below given equation.Weight of KCl to be weighed =Molarity of the solution needed × Molecular weight of KCl (ie, 74.55) × Volume of solution needed in ml / 1000.To prepare 3M KCl in 1 litre, it can be calculated as follows,3 mol × 74.55 g/mol × 1000 ml / 1000 ml = 223.65gByPraveen P Thalichalam, Kasaragod (Dist), Kerala.
No, KCL is not a compound. KCL typically refers to potassium chloride, which is a compound made up of potassium and chloride ions.
Nothing happens. It is still NaCl and KOH.
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
KCl is soluble in DMF
KCl is a compound not an element.
KCl is 'potassium chloride'.
When potassium hydroxide (KOH) is mixed with hydrochloric acid (HCl), a neutralization reaction occurs. This reaction forms potassium chloride (KCl) and water (H2O). The products of this reaction are a salt (KCl) and water.
I did not know that you could get a concentration of 75.66 M KCl, but; Molarity = moles of solute/Liters of solution 75.66 M KCl = moles KCl/1 liter = 75.66 moles of KCl 75.66 moles KCl (74.55 grams/1 mole KCl) = 5640 grams KCl that is about 13 pounds of KCl in 1 liter of solution. This is why I think there is something really wrong with this problem!
it hurts
It dies
you burn.....
It dies.