Calcium
phosphorus
Because while silicon loses electrons to be stable, it loses an electron shell, whereas phosphorus gains more electrons. Therefore, there is a difference of an entire electron shell.
Its outer shell needs 3 more electrons (because 2+3=5) you need 8 in order for the outer shell to become stable being that there is 5 on the outer shell already what plus 5 gives you 8 3 of course so that why you add 3.
Silicon, like carbon, has four valance electrons, and needs another four to have a stable octet.
A chloride anion contains eight outer shell electrons, one more than the seven outer shell electrons found in a chlorine atom.
phosphorus
Phosphorus has 10 more electrons. A neutral atom of phosphorus has 15 electrons, 3 in the outer 3p shell There are 5 electrons in a neutral atom of boron, 1 in the outer 2p shell.
Because while silicon loses electrons to be stable, it loses an electron shell, whereas phosphorus gains more electrons. Therefore, there is a difference of an entire electron shell.
it would be a n-type semiconductor because phosphorus has more valence electrons than silicon does.
Silicon.Neon has 10 electrons. Adding 4 more electrons to that gives 14 electrons, and the configuration of [Ne] 3s2 3p2. This configuration belongs to the element silicon.
No. Chlorine is more reactive than silicon. This is because Chlorine has 7 valence electrons; nearly a full outer shell, while silicon has only 4 valence electrons. An element needs 8 valence electrons to react, and Chlorine only needs one more valence electron before it can react, unlike Silicon, which needs 4.
No. Chlorine is more reactive than silicon. This is because Chlorine has 7 valence electrons; nearly a full outer shell, while silicon has only 4 valence electrons. An element needs 8 valence electrons to react, and Chlorine only needs one more valence electron before it can react, unlike Silicon, which needs 4.
silicon's atomic number is 14 so, its electron configuration is 2.8.4, the third shell needs 4 more electrons to make it 8 and to become stable. ---> so the answer is 4.
This is copied from a similar question to yours fyi. Using boron, phosphorus, and silicon as examples. P-type doping is a process where a silicon atom in the lattice is replaced by a boron atom. A Boron atom has 3 electrons in the outer shell, compared with an electron occupancy of 4 for a silicon atom. So a Boron atom provides a vacancy for any free electrons to occupy with a little effort, when an electron chances to be nearby (the four boron-silicon covalent bonds needs 8 electrons to be stable, but only 7 are provided). The net charge of the material is still zero. More about from where the free electron is coming. N-type doping is using a phosphorus atom to replace a silicon atom. A phosphorus atom has 5 electrons in the outer shell. So a phosphorus atom provides an electron that can be freed with a little effort (the four phosphorus-silicon covalent bonds only need 8 electrons to be stable, each atom needing only to contribute four electrons; the 9th electron will be loosely bound). The net charge of the material is still zero. Where can the electron go? Magic happens when p-type silicon is brought in contact with n-type silicon to form a pn junction. The excess electron vacancies (holes) in p-Si now can exchange with the excess electrons in n-Si, but the net charge of the p-n silicon entity is still zero. However, microscopically, a depletion region is formed at the pn junction, where excess carriers can cross over to the other side. In the p-Si, excess electrons from the n-Si start filling up the holes (the lack of the 8th outer-shell electron to form the four stable boron-silicon covalent bonds) and negatively-charged boron atoms are formed. In the n-Si, excess holes from the p-Si start swallowing up the loosely-bound electrons (the 9th electron in the outer shell) of phosphorus atoms and positively-charged phosphorus atoms are formed. Once formed, and in the absence of an electric field, the depletion region now presents an energy barrier to any further carrier movement and a steady state results -- no net current in the pn junction.
A Covalent bond, because it takes too much energy to gain/lose more than two electrons, thus leaving the option of sharing electrons forming a covalent bond.
Carbon, silicon, germanium are all teravalent atoms (4 electrons in the outer shell). Each element becomes heavier, and (because there are more total electrons) is less "pure" in it's chemical (and electrical) responses.
Its outer shell needs 3 more electrons (because 2+3=5) you need 8 in order for the outer shell to become stable being that there is 5 on the outer shell already what plus 5 gives you 8 3 of course so that why you add 3.