Potassium chloride is that format (K for potassium, CL for chloride). Potassium chlorate, on the other hand, is different (KClO3)
the experimental % oxygen would be lower because there would be more KCL in the simple than oxygen
No: KClO3 is the formula for potassium chlorate, but the formula for potassium chloride is simply KCl.
There is less O in 100 g of [KCl+KClO3]-'mixture' than in 100 g pure [KClO3] because there is more [K] and [Cl] in the first.
Balance manganese dioxide and potassium chlorate is as follows . the formula for potassium chlorate is KClO3 and the one for manganese dioxide is MnO2.so, the reaction is :2 KClO3(s)-> 2 KCl(s)+3 O2(g).
On heating potassium chlorate decomposes on potassium chloride and oxygen. 2KClO3------>2KCl+3O2 9.8g of KClO3 are heated. Calculate a. the mass of KCl formed. b. the mass and volume, at (s.t.p) of O2 formed.
4KClO3= 3KClO4+KCl
the experimental % oxygen would be lower because there would be more KCL in the simple than oxygen
yes KClO3 + heat --> KCl + O2
No: KClO3 is the formula for potassium chlorate, but the formula for potassium chloride is simply KCl.
There is less O in 100 g of [KCl+KClO3]-'mixture' than in 100 g pure [KClO3] because there is more [K] and [Cl] in the first.
2 KClO3 -> 2 KCl + 3 O2.
2KClO3 + HEAT = 2 KCl + 3 O2
KClO3 --> KCl +O2 - hence the use in explosives chlorate normally made by action of Cl2 on KOH. Another contributor says:- KCl + O2 gives rise to KClO3
The chemical reactin is:2 KClO3 = 2 KCl + 3 O24 moles of potassium chlorate produce 6 moles oxygen.
Balance manganese dioxide and potassium chlorate is as follows . the formula for potassium chlorate is KClO3 and the one for manganese dioxide is MnO2.so, the reaction is :2 KClO3(s)-> 2 KCl(s)+3 O2(g).
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
This reaction is:2 KClO3 = 3 O2 + 2 KCl