Assuming the K means Kelvin - which in itself is a measure of temperature.
The freezing point of water is 0°C or 273K in correct SI units.
B. 273K. 5 degrees Celsius is equal to 278K in the Kelvin scale, but the closest value among the given options is 273K.
146c,351k, 133f, 95f, 25c, 58f, 273k
increasing the temperature increases the intermolecular spaces and decreases the intermolecular forces,thus increasing ideality.... so at high temperature of 327c sulphurdioxide is ideal as compared to 273k
At 0 degrees Celsius or 273 Kelvin, nitrogen is a gas. Nitrogen freezes into a solid at a much lower temperature of -210 degrees Celsius or 63 Kelvin.
Celsius.
-273k
273K = -0.15ºCUse this equation to convert Kelvin to degrees Celsius/Centigrade: [°C] = [K] - 273.15
273K = 0oC Hence 98K = 273K - XoC XoC = 98K - 273K = -175oC
-273k
The freezing point of water is 0°C or 273K in correct SI units.
Freezes.
The lowest possible temperature is -273.15 C which equated to '0'K. Therefore, temperature -273K cannot exist. No -ve K temperatures exist.
273K
B. 273K. 5 degrees Celsius is equal to 278K in the Kelvin scale, but the closest value among the given options is 273K.
At 273K and 1 ATM, most gases typically exist in the gaseous state. However, the specific gas present will depend on the composition of the system.
1C= 273k