If you mean the bond type of NaBr3 then it is an ionic compound with ionic bonds.
But I don't know how you can have Na and three Br's because Br's charge is negative one and Na's is plus one so maybe you mean NaBr?
It is a really weird compound that shouldn't happen in theory but probably happens in real life anyways maybe? or not because Br is pretty electronegative so they can't all share one Na.
Sodium Bromate(NaBrO3) and Sodium Bromide(NaBr) should both form bromine when sulfuric acid is added, however Sodium Bromide will not oxidize itself while Sodium Bromate will. With sodium bromide, youd also have to add an oxidizer to get bromine to form. Ive used both hydrogen peroxide and potassium permanganate.
The correct formula for sodium bromate would be NaBrO3. It is formed from sodium (Na), bromine (Br), and oxygen (O), following the typical valency of elements in the same family on the periodic table.
If a compound contains at least one metal atom and at least one nonmetal atom, the compound is ionic. Na (Sodium) is a metal. Br (Bromine) is a nonmetal. Therefore, the compound NaBr is ionic.
Ethanol and NaBr. The delta negative OH dissociates from Sodium creating an +Na ion. The Bromine withdraws the electron density towards itself leaving the Carbon delta +. This means that the -OH will attack the +C removing -Br.
The compound NaBrO3 is called sodium bromate.
Sodium Bromate
To find the number of molecules of NaBrO3 in a 34.5 gram sample, you first need to determine the number of moles of NaBrO3 using its molar mass. Then, you can convert moles to molecules using Avogadro's number (6.022 x 10^23 molecules/mol). Finally, multiply the number of moles by Avogadro's number to get the number of molecules in the sample.
The oxidation states for Na, Br, and O are +1, +5, and -2, respectively. In NaBrO3, there is 1 Na, 1 Br, and 3 O atoms, leading to a total charge of 0. Thus, the oxidation state of NaBrO3 is +5 to balance the charge.
+1 for Na -2 for each O +5 for Br
The one that will dissociate into TWO ions is (2) NaBrO3 (sodium bromate). It will dissociate into Na^+ and BrO3^-.
Sodium Bromate(NaBrO3) and Sodium Bromide(NaBr) should both form bromine when sulfuric acid is added, however Sodium Bromide will not oxidize itself while Sodium Bromate will. With sodium bromide, youd also have to add an oxidizer to get bromine to form. Ive used both hydrogen peroxide and potassium permanganate.
The correct formula for sodium bromate would be NaBrO3. It is formed from sodium (Na), bromine (Br), and oxygen (O), following the typical valency of elements in the same family on the periodic table.
I don't think there is such a substance. The nearest would be sodium bromate. NaBrO3
Actually there are a few KBrO3 or NaBrO3 etc - in the bromate ion, bromine is in oxidation state +7
If a compound contains at least one metal atom and at least one nonmetal atom, the compound is ionic. Na (Sodium) is a metal. Br (Bromine) is a nonmetal. Therefore, the compound NaBr is ionic.
HCl(aq) + C6H5COONa(aq) --> C6H5COOH(s) + NaCl(aq)