Sodium hypochlorite NaOCl may react with two moles of HCl,
NaOCl + 2HCl = NaCl + Cl2+ H2O, so its molecular mass divided by 2 is its equivalent mass.
The weight of sodium hypochlorite (bleach) varies depending on the concentration. Bulk users (municipal water treatment, manufacturing, cooling towers) most frequently use 12.5% sodium hypochlorite which weighs 10 lbs. per gallon.
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The equivalent weight is the gram molecular weight divided by the number of electrons lost or gained by each molecule; e.g., potassium permanganate (KMnO4) in acid solution, 158.038/5 g; potassium dichromate (K2Cr2O7), 294.192/6 g; and sodium thiosulfate (Na2S2O3·5H2O), 248.1828/1 g. In case of Sodium Thiosulfate the reation proceeds as under: I2 + 2 Na2S2O3 → Na2S4O6 + 2 NaI 2 Na2S2O3 ≡ I2 ≡ Cl2 ≡ 2 e Hence Na2S2O3 ≡ 1 e Thus Molecular weight devded by 1 is the equivalent weight & hence both have same value
Weight 4.0 g dry NaClO and add it to about 90 mL water, dissolve completely and fill up till 100 mL exactly: then you've got a 4.0 g/100 mL solution. (This is almost 4.00%).
Sodium Chloride is NaCl. Atomic weight of sodium (Na) is 23 and that of Chlorine (Cl) is 35.5 . Molecular weight of Sodium Chloride is 58.5. Percentage of Chlorine in Sodium Chloride is (35.5 / 58.5) * (100%) = 60.7 %
It means 14% of the molecules of the sodium Hypochlorite solution contain the "free-chlorine" required to actually do the desired job of the Hypochlorite. Effectively, only 14% of the mass or moles of the Hypochlorite will react.
By weight, 5.25% sodium hypochlorite and 94.75% water.
Answer #1By weight, 5.25% sodium hypochlorite and 94.75% water.
The weight of sodium hypochlorite (bleach) varies depending on the concentration. Bulk users (municipal water treatment, manufacturing, cooling towers) most frequently use 12.5% sodium hypochlorite which weighs 10 lbs. per gallon.
The formula for sodium acetate is CH3COONa and the equivalent weight is the same as the molecular weight (molar mass) which is 82.0343 g/mol.
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its equal number of electrons wich less from componed
Sodium is monofunctional. Thus its molecular weight and equivalent weight are identical. So there are 10 milliequivalents of sodium in 10 millimoles.
Thio: 1 mole S2O32- = 2 equivalent So Eq. mass = 0.5 * (molar mass)