2NaHSO3 + Br2 + H2O = NaBr + NaOBr + SO2 + H3O+
I am not happy with this answer - you have a positive charge appearing from nowhere. Also NaHSO3 is sodium bisulfite the questioner asked for sodium metabisulfite which is Na2S2O5 . However, sodium metabisulfite in the presence of water does convert to sodium bisulfite Na2S2O5 + H2O = 2NaHSO3
2NaHSO3 + Br2 + H2O = 2NaBr + H2SO4 + H2SO3
When bromine and sodium combine, they react to form sodium bromide. This is a salt that is water soluble and a common source of bromine in various chemical applications. The reaction between bromine and sodium is a redox reaction where sodium loses an electron to bromine.
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr
The reaction between aqueous chlorine and sodium bromide solution results in the displacement of bromine by chlorine, forming sodium chloride and bromine gas as products. This is a redox reaction where chlorine is reduced and bromine is oxidized.
When sodium chloride and bromine water are mixed, a red-brown color will develop due to the reaction between bromine and chloride ions. This reaction forms bromide ions and an aqueous solution of sodium bromide.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
When bromine and sodium combine, they react to form sodium bromide. This is a salt that is water soluble and a common source of bromine in various chemical applications. The reaction between bromine and sodium is a redox reaction where sodium loses an electron to bromine.
Sodium and bromine are chemical elements, not properties; the chemical reaction between sodium and bromine is a chemical process, not a property.
2NaI(aq)+Br2(l)-->2NaBr(aq)+I2(l) Sodium iodide+bromine-->sodium bromide+iodine
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr
The reaction between aqueous chlorine and sodium bromide solution results in the displacement of bromine by chlorine, forming sodium chloride and bromine gas as products. This is a redox reaction where chlorine is reduced and bromine is oxidized.
The balanced chemical equation for the reaction between bromine and sodium thiosulfate is: 2Na2S2O3 + Br2 → 2NaBr + Na2S4O6. This reaction is often used in titrations to determine the concentration of bromine in a solution.
Bromine loses an electron and forms a bromide ion by gaining one electron in the reaction with sodium. Sodium donates its electron to bromine, making the bromine atom gain one electron and become a bromide ion during the reaction.
Yes, bromine reacts with sodium to form sodium bromide. This reaction is a displacement reaction where bromine replaces another element in a compound.
When sodium reacts with bromine, they form sodium bromide. This is a redox reaction where sodium loses an electron to bromine, which gains an electron to form the bromide ion. The reaction is highly exothermic and can be violent if not controlled.
In the reaction between bromine and sodium, bromine gains an electron to form the bromide ion (Br^-). This process is known as reduction, where bromine undergoes a gain of electrons and a decrease in oxidation state.
Yes, bromine will react with sodium. When bromine comes in contact with sodium, they will react to form sodium bromide, a white solid compound. This reaction is a redox reaction where bromine gets reduced and sodium gets oxidized.
no reaction