2NaHSO3 + Br2 + H2O = NaBr + NaOBr + SO2 + H3O+
I am not happy with this answer - you have a positive charge appearing from nowhere. Also NaHSO3 is sodium bisulfite the questioner asked for sodium metabisulfite which is Na2S2O5 . However, sodium metabisulfite in the presence of water does convert to sodium bisulfite Na2S2O5 + H2O = 2NaHSO3
2NaHSO3 + Br2 + H2O = 2NaBr + H2SO4 + H2SO3
sodium metabisulfite oxidizes best in an alkaline (basic solution). In low pH (2-3) the reaction occurs very slowly or not at all..
Chlorine displaces bromine as it is more reactive, and it creates sodium chloride aqueous and bromine aqueous.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
Bromine will be reduced to bromide and it will oxidize Sodium thiosulfate to Sodium tetrathionate :2 Na2S2O3 + Br2 ----> Na2S4O6 + 2 NaBr
AgBr precipitates and in light decomposes to bromine and silver metal.
Sodium and bromine are chemical elements, not properties; the chemical reaction between sodium and bromine is a chemical process, not a property.
sodium metabisulfite oxidizes best in an alkaline (basic solution). In low pH (2-3) the reaction occurs very slowly or not at all..
no reaction
its chemestry
2NaI(aq)+Br2(l)-->2NaBr(aq)+I2(l) Sodium iodide+bromine-->sodium bromide+iodine
Chlorine displaces bromine as it is more reactive, and it creates sodium chloride aqueous and bromine aqueous.
Br2 + 3NaHSO3 = 2NaBr + NaHSO4 + H2O + 2SO2
Well, if your talking about the reaction between sodium bromide (NaBr) and Iodine, then I don't think that it will replace bromine. Bromine is higher on the reactivity series, so if they come into contact with each other, there won't simply be any reaction
Bromine will be reduced to bromide and it will oxidize Sodium thiosulfate to Sodium tetrathionate :2 Na2S2O3 + Br2 ----> Na2S4O6 + 2 NaBr
Any reaction occur.
An extremely exothermic reaction occurs producing Sodium Bromide
AgBr precipitates and in light decomposes to bromine and silver metal.