2-
+6This compound has dichromate in it (Cr2O7-2). Oxygen almost always has an oxidation state of -2, which means the total charge for the oxygens is -14. The charge on the two chromates combined needs to be two less than the total charge on the oxygens because the ion has an overall charge of -2. Thus, the oxidation state for Cr is +6.
Mn(II)(C2H3O2)2 That's one Manganeese with charge (+2) with two molecules of acetate (two carbons, three hydrogens, and two oxygens) with a net charge of (-1) per molecule
The carbon compound with one carbon and two oxygens is carbon dioxide (CO2).
The valency of sulfate ion (SO4^2-) is -2 because sulfur contributes a charge of +6 and each oxygen contributes a charge of -2, resulting in a total charge of -2 for the sulfate ion. This allows for the ion to form stable ionic compounds with metals and other cations.
Copper ethanoate in solution consists of two parts: Ethanoate ion: (CH3 - COO)- (to note this has a negative charge on the COO represented by the - and a bond after CH3 also represented by a -) This has only single bonds from both oxygens to the carbon, the charge is then spread across the two oxygens and the carbon making the molecule polar and soluble Copper ion: Cu2+ ions have a 2+ charge and so are in solution (generally anything with a charge will be in solution) When this is dehydrated the copper ethanoate is formed as a precipitate using 2 ethanoate ions and 1 copper ion to give a charge of 0 throughout the molecule. The formulae of this is Cu(CH3COO)2 (the 2 is supposed to be subscript) This is an answer to another question to which my answer also fits this one. So yes copper ethanoate is soluble.
The charge for CrO4 is 2-. This is because the oxygens in the molecule each have a charge of 2-, so the overall charge is balanced by the chromium having a charge of 2+.
In PO3^3-, the oxidation state of the phosphorus atom is +3. Each oxygen contributes -2 charge, so 3 oxygens would contribute a total charge of -6, which is balanced by the +3 charge of the phosphorus atom. In PO3^3-, the oxidation state of the phosphorus atom is +5. Each oxygen contributes -2 charge, so 3 oxygens contribute a total charge of -6. This is balanced by the +3 charge of the phosphorus atom, resulting in an oxidation state of +5.
Aluminum oxide is a neutral compound, so it does not have a net charge. Each aluminum atom in aluminum oxide has a charge of +3, while each oxygen atom has a charge of -2, resulting in a balanced compound with no overall charge.
+6This compound has dichromate in it (Cr2O7-2). Oxygen almost always has an oxidation state of -2, which means the total charge for the oxygens is -14. The charge on the two chromates combined needs to be two less than the total charge on the oxygens because the ion has an overall charge of -2. Thus, the oxidation state for Cr is +6.
+6 for each sulphur. +1 for each Na; Two oxygens are as peroxides and will have -1 charge / oxidation number each. Six oxygens are as oxides and will have -2 charge each. So, 2(+1) + 2y + 2(-1) + 6(-2) = 0 Or y = +6 (the charge / oxidation number of sulphur)
Ribose has 10 hydrogens and 5 oxygens.
it has no oder .
The bond angle between the oxygens in SeO2 is approximately 120 degrees.
The hybridization of both oxygens in a carboxylic acid group is sp.
The simplest answer is that none of the oxygens in N2O5 have a -2 formal charge, so giving nitrogen a +5 formal charge would lead to a charge imbalance. Since the molecule must be charge neutral, we know that the nitrogen must have a different formal charge. (Proof by Contradiction) The more complicated answer requires a discussion of the bonding in N2O5. As explained in the video in the Related Link, each of the nitrogens sits touching three oxygens, with one of these three being shared with the other nitrogen. The "middle" oxygen is single-bonded to each nitrogen, meaning that the oxygen in question has a 0 formal charge. On the extremities, there are two oxygens that are single-bonded to a nitrogen and two oxygens that are double-bonded. The single-bonded ones have a -1 formal charge and the double bonded ones have a 0 formal charge. This makes the total formal charge coming from the five oxygens to be 0+0-1-1+0 = -2. Therefore the nitrogens must each be +1 since the structure is parallel and the charge must be neutral. Oh dear what a strange question. In simple classical pre- GN Lewis octet rule following the definition of valency the valency of N is 5. two double bonds one single surrounding each N. (this old theory would give 10 valence electrons around the N) From an oxidation number point of view (sometimes termed valency these days) the N atoms oxidation #'s are +5. However if you apply the octet rule you get a different answer , involving charged structures which in valence bond theory resonate. This is I think what the answer above is getting at.
Oxygen is in p block. it is a useful gas. oxygens atomic number is 8.
The molecular geometry of the oxygens in hydrogen peroxide (H2O2) is bent or angular.