Cl-CH3_CH2_CH2_CH3+C2H5oNa_> C6H15o+
give equation of 2 iodo hexane with sodium methoxide
React sodium metal with ethanol.
you will get Sodium ethoxide and hydrogen gas
They both have OH. However, in sodium hyrdroxide, the OH- group is attached to the Na+ by an ionic bond. When dissolved it water, OH- would become free ions. On the other hand, in alcohol, the OH is attached to a carbon atom by a covalent bond. It is not an ion. Therefore is would not dissociate in water.
Sodium reacts with Ethanol to produce Sodium Ethoxide (C2H5ONa) and Hydrogen gas (H2), according to the following equation.2 C2H5OH + 2Na ----> 2 C2H5ONa + H2
It is physical, change of state, just cooling down
Sodium Ethoxide
React sodium metal with ethanol.
C2H5ONa.
you will get Sodium ethoxide and hydrogen gas
Sodium ethoxide and hydrogen gas.2CH3CH2OH + 2Na ---> 2CH3CH2O-Na+ + H2
It will create sodium ethoxide. The balanced equation would be 2C2H5OH + 2Na ==> 2C2H5ONa + H2.
Alcohols react with NaOH, as ethanol forms sodium ethoxide with NaOH.
when sodium react with ethanol ,ethoxide and hydrogen are formed. this reaction is like when sodium reacts with water
They both have OH. However, in sodium hyrdroxide, the OH- group is attached to the Na+ by an ionic bond. When dissolved it water, OH- would become free ions. On the other hand, in alcohol, the OH is attached to a carbon atom by a covalent bond. It is not an ion. Therefore is would not dissociate in water.
Because the sodium metal will react with the oxygen in the alcohol. CH3CH2OH + Na =
NaC2H5O
no rection takes place.because two of the compounds are already oxidized n r therefore inert(unreactive).