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When solid sodium hydroxide dissolves in water, the water heats up, demonstrating that the process of dissolving is exothermic for NaOH. (Very exothermic, in fact, releasing about 45kJ of heat per mole dissolved -- enough to heat a liter of H2O by 10C!)

Since heat can be thought of as a product in an exothermic reaction, the equation is:

NaOH (s) ---> Na+ (aq) + OH_ (aq) + 45kJ

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Q: What is the balance equation for the reaction sodium hydroxide with water in an exothemic reaction?
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