3H2 + N2 --> 2NH3 Since Hydrogen (H) and Nitrogen (N) both appear in nature diatomically they only appear as H2 and N2. We must add 3 molecules of Hydrogen and 1 molecule of Nitrogen to get 2 molecules of ammonia. We cannot, in nature, have half of a diatomic Hydrogen or Nitrogen atom, for that reason the equation must yield 2 molecules of Ammonia.
N2 + 3h2 ---> 2nh3
3H2 + N2 --> 2NH3
3H2 (g)+ N2 (g)= 2 NH3 (g)
3h2 + n2 = 2nh3
NH3
2H2 + 2NO --> 2H2O + N2
Nitrogen & Hydrogen.
2NF3 --> N2 + 3F2
2 no + o2 -> 2 no2
2H2+ 2NO yield 2H20 + N2
3h2 + n2 = 2nh3
4H2 + N2 --> 2H4N+
2H2 + 2NO --> 2H2O + N2
the balanced equation is N2 + 3H2 = 2NH3
3H2 + N2 yields 2NH3
Nitrogen Gas + Hydrogen Gas --> Ammonia Gas Or 2H3 + N2 --> 2NH3 This is a balanced equation. The general formula for ammonia is NH3
N2 + 3H2 --> 2NH3 N2 + 3H2 --> 2NH3
NH3 or ammonia is the hydride of nitrogen.
Yes - there are equal values of nitrogen (4) and hydrogen (12) on both sides of this equation, and all molecular formulas are in empirical form.
Nitrogen is a diatomic gas so it would be N2.
Nitrogen & Hydrogen.
I assume you want to know the balanced equation. Here it is- N(2) + 3 H(2) ---> 2 NH(3).