Well, well, well, aren't we feeling fancy with our chemistry questions? The balanced equation for barium chloride and potassium sulfate is BaCl2 + K2SO4 → BaSO4 + 2KCl. Don't worry, I won't charge you extra for the chemistry lesson!
(NH4)2SO4(aq) + BaCl2(aq) → 2NH4Cl(aq) + BaSO4(s). Barium sulfate is the precipitate.
Na2SO4 +CaCl2---------------> 2NaCL +CaSo4
Barium hydroxide and ammonium sulfate react to form barium sulfate and ammonium hydroxide: Ba(OH)2 + (NH4)2SO4 -> BaSO4 + 2NH4OH Potassium phosphate and calcium chloride react to form potassium chloride and calcium phosphate: 2K3PO4 + 3CaCl2 -> 6KCl + Ca3(PO4)2
CuSO4(aq) + BaCl2(aq) -> CuCl2(aq) + BaSO4(s)
The reaction between ammonium sulfate (NH4)2SO4 and potassium hydroxide (KOH) produces ammonium hydroxide (NH4OH) and potassium sulfate (K2SO4). The balanced equation is: (NH4)2SO4 + 2KOH → 2NH4OH + K2SO4
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
The balanced chemical equation for this reaction is K2SO4 + BaCl2 → 2KCl + BaSO4. The formula unit shows the ratio of ions combining to form the products: 2 potassium ions combine with 1 sulfate ion to form potassium sulfate, while 1 barium ion combines with 2 chloride ions to form barium chloride.
The balanced equation for copper sulfate (CuSO4) and potassium phosphate (K3PO4) reacting is: 3CuSO4 + 2K3PO4 -> Cu3(PO4)2 + 3K2SO4
The reaction between barium chloride and potassium sulfate results in the formation of insoluble barium sulfate and soluble potassium chloride. This is a double displacement reaction where the cations and anions switch partners. The balanced chemical equation for this reaction is BaCl2 + K2SO4 -> BaSO4 + 2KCl.
The balanced equation for Iron (III) chloride reacting with copper (II) sulfate is: 2FeCl3 + 3CuSO4 → Fe2(SO4)3 + 3CuCl2
The balanced equation for potassium hydroxide (KOH) reacting with sulfuric acid (H2SO4) to form potassium sulfate (K2SO4) and water (H2O) is 2KOH + H2SO4 → K2SO4 + 2H2O.
The balanced equation for the reaction between barium sulfate (BaSO4) and calcium chloride (CaCl2) is BaSO4 + CaCl2 -> BaCl2 + CaSO4. This reaction forms barium chloride (BaCl2) and calcium sulfate (CaSO4) as products.
This equation is BaCl2 (aq) + Na2SO4 (aq) -> 2 NaCl (aq) + BaSO4 (s).
Aluminium Sulphate and potassium hydroxide. Al2(SO4)3 + 6KOH = 3K2(SO4) + 2Al(OH)3
Ba2+ + [2Cl- + 2Na+] + SO42---> BaSO4 + [2Cl- + 2Na+]Ba2++ SO42- --> BaSO4
BaCl2(aq) + Na2SO4 (aq) ------> BaSO4(s) + 2NaCl(aq)