2KBr + 2H2O----->2KOH + Br2 + H2(g)
this is the reaction in electrolysis of KBr in aqueous solution
2KI + Cl2 = 2KCl + I2
This is the correct answer: Cl2(g)+2KI(aq) = I2(s)+2KCl(aq)
The net ionic equation for the reaction between aqueous potassium iodide (KI) and aqueous lead(II) nitrate (Pb(NO3)2) is: 2I- (aq) + Pb2+ (aq) → PbI2 (s)
When aqueous solutions of potassiumfluoride and hydrobromic acid are mixed, an aqueous solution of potassiumbromide and hydrofluoric acidresults. Write the net ionic equation for the reaction.
2NH4Cl (aq) + Pb(NO3)2 (aq) ----> 2NH4NO3 (aq) + PbCl2 (s)
The balanced equation is: K2CO3(aq) + BaCl2(aq) -> 2KCl(aq) + BaCO3(s).
The balanced equation for the dissociation of water is: 2H2O (liquid) ⇌ 2H+ (aqueous) + O2- (aqueous)
When aqueous potassium hydroxide is reacted with sulfur dioxide, potassium sulfite (K2SO3) and water are produced. The balanced chemical equation for the reaction is: 2KOH + SO2 → K2SO3 + H2O.
2KI + Cl2 = 2KCl + I2
The balanced chemical equation for neutralizing aqueous acetic acid (HC2H3O2) with aqueous potassium hydroxide (KOH) is: HC2H3O2 + KOH → KC2H3O2 + H2O This reaction forms potassium acetate (KC2H3O2) and water (H2O) when acetic acid reacts with potassium hydroxide in a 1:1 molar ratio.
CH3COOH + KOH = CH3COOK + H2O
This is the correct answer: Cl2(g)+2KI(aq) = I2(s)+2KCl(aq)
The balanced equation for ammonium phosphate in an aqueous solution is: (NH4)3PO4(aq) → 3NH4+(aq) + PO43-(aq)
KOH(aq)+HC2H3O2(aq)---- H2O(l)+KC2H3O2(aq)
no reaction occurs .. they just mix together.
The net ionic equation for the reaction of aqueous potassium iodide with aqueous lead (II) nitrate is: 2I⁻(aq) + Pb²⁺(aq) -> PbI₂(s)
This equation is NaClO (aq) + 2 HCl (aq) = NaCl (aq) + Cl2 + H2O.