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Aluminium forms two oxdiation states with the chloride ion, I and III

3AlCl + Na3PO4 ------------> NaCl + Al3PO4 this is for Aluminum I chloride

AlCl3 + Na3PO4 ------------> AlPO4 + 3 NaCL for the Aluminum III chloride

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11y ago
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Wiki User

15y ago

This purely is elementary Chemistry, only a Chemistry noob would not know how to do this.

Noobness aside, the answer is 3Al + 3NH4ClO4 --> Al2O3 + AlCl3 + 3NO + 6H2O

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Wiki User

13y ago

alcl4+cl3

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Q: What is the balanced equation of aluminum chloride and sodium phosphate?
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