Most people will answer this:
ZnCl2 + 2AgNO3 --> Zn(NO3)2 + 2AgCl
But actually in solution (where this reaction could only take place!) only two of 4 ions react:
Cl- + Ag+ --> (AgCl)s
The other ions: NO3- and Zn2+ stay unchanged in solution (tribune ions)
if lead has an ion charge of +2:
3Pb(NO3)2+ 2Na3PO4 ---> Pb3(PO4)2+ 6NaNO3
if lead has an ion charge of +4:
3Pb(NO3)4+ 4Na3PO4 ---> 12Pb3(PO4)4+ NaNO3
Assuming you meant iron nitrate instead of sodium nitrate,
FeCl2 + Pb(NO3)2 --> PbCl2 + Fe(NO3)2
Otherwise,
2NaCl + Pb(NO3)2 --> PbCl2 + 2NaNO3
sodium chloride: NaCl lead nitrate: Pb(NO3)2
Pb(NO3)2 + 2 NaCl -> PbCl2 + 2 NaNO3
ZnCl2 +Pb(NO3)2 => Zn(NO3)2 + PbCl2
no reaction
2AgNO3 + MgBr2 ----> 2AgBr + Mg(NO3 ) 2
The balanced equation for the reaction is AgNO3 (aq) + NaCl (aq) -> AgCl (s) + NaNO3. The coefficient of each reactant is the implied 1 when no explicit coefficient is shown in the equation. Therefore the same number of moles of silver nitrate as of sodium chloride are required for the reaction.
The balanced equation is: Ca(NO3)2 + 2NaOH → Ca(OH)2 + 2NaNO3
Silver Nitrate + Sodium Chloride --> Silver Chloride + Sodium Nitrate AgNO3 + NaCl --> AgCl + NaNO3 The four ionic equations are: AgNO3 --> Ag+ + NO3- NaCl --> Na+ + Cl- Ag+ + Cl- --> AgCl Na+ + NO3- --> NaNO3 Since the oxidation states of all four ions present in the equation don't change before or after the reaction. Therefore, I don't think there's a net ionic equation. The reaction above is just a displacement or precipitation (AgCl is insoluble, therefore it forms a white precipitate after the reaction) reaction.
2NaCl+Pb(NO3)2==== 2NaNO3+PbCl2
No reaction
87
The reaction is:AgNO3 + NaCl = NaNO3 + AgCl(s).
Any reaction occur in this case.
One balanced equation for the reaction between elemental copper and silver nitrate is Cu + AgNO3 -> CuNO3 + Ag.
the chemical equation for beryllium chloride reacts with silver nitrate in water to form beryllium nitrate and silver chloride can be written as follows .BeCl2 +2 Ag NO3 -> Be (NO3) 2 +2AgCl.A balanced equation has equal numbers of each type of atom on each side of the equation.
To determine the mass of silver chloride produced, we need to know the balanced chemical equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) that produces silver chloride (AgCl) as a precipitate. Once we have the balanced equation, we can use the stoichiometry of the reaction to determine the number of moles of AgCl produced, and then convert that to mass using the molar mass of AgCl.
The reaction is:2 AgNO3 + CaCl2 = 2 AgCl(s) + Ca(NO3)2
no reaction
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
There shall be none as both compounds have same anions (Nitrates)