The chemical formula of tin IV acetate is Sn(C2H3O2)4.
Nothing happens, all possible salts are very soluble: Potassium and sodium salts are always soluble!
Silver nitrate solution and potassium iodide solution can be mixed to form silver iodide due to a double displacement reaction where the silver ions from silver nitrate react with the iodide ions from potassium iodide to form insoluble silver iodide precipitate. The balanced chemical equation for this reaction is: AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq).
NaI­(aq)­­ + AgNO3(aq) à NaNO3(aq) + AgI(s)
AgNO3 is essentially a positive Ag ion and negative NO3 polyatomic ion. it is a test for halide ions like I minus. So Ag+(charge) + I-(charge) -->AgI in which case a white precipitate should form, confirming the presence of iodide.
This equation is: 2 AgNO3 + K2CrO4 => Ag2CrO4 + 2 KNO3.
Nothing happens, all possible salts are very soluble: Potassium and sodium salts are always soluble!
No reaction because the anion is common in both compounds.
Silver nitrate solution and potassium iodide solution can be mixed to form silver iodide due to a double displacement reaction where the silver ions from silver nitrate react with the iodide ions from potassium iodide to form insoluble silver iodide precipitate. The balanced chemical equation for this reaction is: AgNO3 (aq) + KI (aq) → AgI (s) + KNO3 (aq).
When copper sulfate solution is mixed with potassium iodide, a solid precipitate of copper iodide is formed, while potassium sulfate remains in solution. This reaction is a double displacement reaction. The balanced chemical equation is CuSO4 + 2KI → CuI2 + K2SO4.
When acetone is mixed with sodium hydroxide and potassium iodide, no significant chemical reaction occurs due to the absence of a strong oxidizing or reducing agent in the combination. The reaction is non-redox and no new compounds are formed.
NaI­(aq)­­ + AgNO3(aq) à NaNO3(aq) + AgI(s)
When iodide is mixed with silver nitrate, a yellow precipitate of silver iodide is formed due to a double displacement reaction. This reaction can be represented by the chemical equation: 2AgNO3 + 2KI → 2AgI + 2KNO3.
Zinc iodide and silver nitrate react to produce zinc nitrate and silver iodide. The balanced chemical equation for this reaction is: ZnI2 + 2AgNO3 → 2AgI + Zn(NO3)2. Silver iodide is a yellow precipitate that forms when the two solutions are mixed.
Pb(NO3)2 + 2KI -> PbI2 + 2KNO3.
Lead(II) nitrate and sodium iodide undergo a double displacement reaction to form sodium nitrate and lead(II) iodide, which is a slightly soluble yellow solid. The balanced chemical equation for this reaction is: Pb(NO3)2(aq) + 2NaI(aq) -> 2NaNO3(aq) + PbI2(s)
When Pb(NO3)2 (lead nitrate) is mixed with KI (potassium iodide), a yellow precipitate of lead iodide (PbI2) is formed. This reaction can be represented by the equation: Pb(NO3)2 + 2KI -> 2KNO3 + PbI2.
PbI2 (aq) + 2AgNO3 (aq) --> 2AgI (s) + Pb(NO3)2 (aq)