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HI has a bond order of 1. H 1s1 + I 5p5 gives one filled (2 electrons) sigma bonding oribital and one empty anti-bonding orbital.

bond order= 1/2 (bonding electrons-anti-bonding electrons)

= 1/2(2-0)

= 1

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Q: What is the bonding order of hydrogen iodide?
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