Calcium hydroxide, a base, will reaction with phenol, a weak acid in a neutralization reaction to give a salt (calcium phenoxide (Ca(PhO-)2) and water.
Pyrogallic acid and sodium hydroxide is used to provide anaerobiosis.
The reaction between cyclohexane and sodium hydroxide involves hydrolysis of cyclohexane to cyclohexanol and cyclohexanone. It can be represented by the equation: C6H12 + NaOH → C6H11OH + NaX (where X is an anion)
The reaction between sodium oxide (Na2O) and water (H2O) forms sodium hydroxide (NaOH). The chemical equation for this reaction is: Na2O + H2O -> 2NaOH
The equation for the reaction between phosphoric acid (H3PO4) and ammonium hydroxide (NH4OH) is: H3PO4 + NH4OH -> (NH4)3PO4 + H2O This balanced equation shows the chemical reaction where phosphoric acid reacts with ammonium hydroxide to form ammonium phosphate and water.
CaCl2 + 2H2O so it makes Calcium chloride and water. ==
The chemical equation for the reaction between ethanoic acid (acetic acid) and sodium hydroxide is: CH3COOH + NaOH → CH3COONa + H2O This reaction is a neutralization reaction that forms sodium acetate and water.
Pyrogallic acid and sodium hydroxide is used to provide anaerobiosis.
The reaction is the following: H2SO4 + 2NaOH = Na2SO4 + 2H2O
Potassium oxide(K2O) + water(H2O) --> potassium hydroxide(2KOH)
The chemical equation for the reaction between aluminum sulfate and calcium hydroxide is: Al2(SO4)3 + 3Ca(OH)2 -> 3CaSO4 + 2Al(OH)3
When sodium hydroxide reacts with methanol, a neutralization reaction occurs, forming sodium methoxide and water. The balanced chemical equation for this reaction is: CH3OH + NaOH → CH3ONa + H2O
The reaction between ethanoic acid and ammonium hydroxide forms ammonium acetate, water, and ammonia gas. The balanced chemical equation for this reaction is: CH3COOH + NH4OH -> NH4CH3COO + H2O + NH3.
Acid base reaction. HCl + NaOH >> NaCl + H2O
This chemical reaction is: CaO + H2O = Ca(OH)2.
The chemical equation for the reaction between ethyl iodide and aqueous potassium hydroxide is: C2H5I + KOH → C2H5OH + KI This reaction involves the substitution of the iodine in ethyl iodide with hydroxide from KOH, resulting in the formation of ethanol and potassium iodide.
The reaction between sodium hydroxide and sodium carbonate can be represented by the following equation: 2NaOH + Na2CO3 -> 2Na2CO3 + H2O
Sulfuric acid + Beryllium Hydroxide → Berylium Sulfate + 2 Water H2SO4 + Be(OH)2 → Be SO4 + 2H2O